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ASHA 777 [7]
3 years ago
7

What is the area of each piece of the composite figure?

Mathematics
1 answer:
Valentin [98]3 years ago
3 0
The top square is 8. The long rectangle 19.5. The bottom rectangle is 3.
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A 16\dfrac1216 2 1 ? kilometer stretch of road needs repairs. Workers can repair 2\dfrac142 4 1 ? kilometer of road per week. Ho
olganol [36]

Answer:

7\frac{1}{3} weeks.

Step-by-step explanation:    

We have been given that a 16\frac{1}{2} km stretch of road needs repairs. Workers can repair 2\frac{1}{4} kilometer of road per week.

To find the number of weeks it will take to repair the stretch we will divide 16\frac{1}{2} by 2\frac{1}{4}

\text{Number of weeks it will take to repair the stretch of road}=16\frac{1}{2}\div 2\frac{1}{4}

Upon converting our mixed fractions into improper fractions we will get,

\text{Number of weeks it will take to repair the stretch of road}=\frac{33}{2}\div \frac{9}{4}

Dividing a fraction with another fraction is same as multiplying the 1st fraction with the reciprocal of second fraction.

\text{Number of weeks it will take to repair the stretch of road}=\frac{33}{2}\times \frac{4}{9}

\text{Number of weeks it will take to repair the stretch of road}=\frac{33*2}{9}

\text{Number of weeks it will take to repair the stretch of road}=\frac{11*2}{3}

\text{Number of weeks it will take to repair the stretch of road}=\frac{22}{3}

\text{Number of weeks it will take to repair the stretch of road}=7\frac{1}{3}

Therefore, it will take 7\frac{1}{3} weeks to repair the stretch of the road.

3 0
3 years ago
Write an equation in point slope formula of the line that passes through point (-3,0) and has a slope of -1/3
olasank [31]

Answer:

Step-by-step explanation:jdjdjsjsjsjssjjsns

8 0
4 years ago
A collection of 30 coins worth $5.50 consists of nickels, dimes, and quarters. There are twice as many dimes as nickels. How man
defon
Three unknowns requires three equations to solve . . .

1) n + d + q = 30
2) d = 2n
3) (0.05)n + (0.10)d + (0.25)q = 5.50

* plug 2) into 1) and solve for q

n + 2n + q = 30

3n + q = 30

q = 30 - 3n

* now we have variables d and q expressed in terms of n, so we plug those equations into 3) and solve for n . . .


0.05n + 0.10(2n) + 0.25(30 - 3n) = 5.50

0.05n + 0.20n + 7.50 - 0.75n = 5.50

(0.05 + 0.20 - 0.75)n + 7.50 = 5.50

-0.50n + 7.50 = 5.50

-0.50n = 5.50 - 7.50

-0.50n = -2.00

n = -2.00/-0.50 = 4

d = 2n = 2(4) = 8

q = 30 - 3n = 30 - 3(4) = 30 - 12 = 18

The answer is . . .

n = 4 nickels
d = 8 dimes
q = 18 quarters

. . . for a total of (4 + 8 + 18) = 30 coins
. . . 8 dimes is twice 4 nickels
. . . $0.05(4) + $0.10(8) + $0.25(18) = $5.50
3 0
3 years ago
|x+7|&gt;3<br><br> help me pleaseeee
Nady [450]

Answer:

x>-4

Step-by-step explanation:

|x+7| is just x+7

x+7>3

-7 on both sides

x>-4

5 0
3 years ago
Read 2 more answers
Hey i need help please
Zanzabum
3634 rounds up to 4000 and 304 rounds down to 300. 4000 * 300 = 1,200,000
5 0
3 years ago
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