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3 years ago

14

Last month we had twelve days of either corn or carrots in the cafeteria for lunch. There were six more days of corn than carrot

s. How many days did we have corn?
A.
3 days

B.
6 days

C.
9 days

D.
12 day

1 answer:

telo118 [61]3 years ago

8 0

The answer would be D

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Please help its urgent!!!!

Elenna [48]

Answer:

A

Step-by-step explanation:

5 0

3 years ago

A 154-lb person burns 420 calories per hour riding an exercise bicycle at a rate of 15 mi/hr. Write a function rule to represent

nika2105 [10]

<span>C = total calories burned
r = rate of burning calories = 420 calories burned/hour
t = time in hours
C = 420 * t
</span>

4 0

3 years ago

In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini

svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

$x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2$

The augmented matrix is

$\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]$

The reduction of this matrix to row-echelon form is outlined below.

$R_2\rightarrow R_2-R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]$

$R_3\rightarrow R_3-2R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]$

$R_3\rightarrow R_3-R_2$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]$

The last row determines, if there are solutions or not. To be consistent, we must have k such that

$k^2-k-2=0$

$\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2$

Case k = −1:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]$

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]$

This gives the infinite many solution.

5 0

3 years ago

What is 7/8-1/2 in simplest form

adell [148]

The answer to your question is 3/8.

6 0

3 years ago

Read 2 more answers

Plz aswer and explain this to me i dont get it

WINSTONCH [101]

Answer: 36

Step-by-step explanation:

1) Find the prime factorization of 12

12=2*2*3

2) Find the prime factorization of 18

18=2*3*3

3) Multiply each factor the greater number of times it occurs in the first two steps above to find the LCM.

LCM=2*2*3*3

4) LCM=36

8 0

4 years ago