Answer: 48
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Define the number of cakes they baked in term of x
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Let the number of cakes Kay baked be x
Kay = x
Tim = 3x ← Tim baked 3 times as many as Kay
Griff = 1.5x ← Griff baked 1/2 as many as Tim
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Construct the equation and solve for x
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The total number of cakes baked was 88.
x + 3x + 1.5x = 88 ← Combine like terms
5.5 x = 88 ← Divide by 5.5
÷5.5 ÷5.5
x = 16
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Find the number of cakes each baked
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Kay = x = 16
TIm = 3x = 16 x 3 = 48
Griff = 1.5x = 1.5(16) = 24
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Answer: Tim baked 48 cakes.
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Answer:
8x²- x -8
Step-by-step explanation:
The question is not well written. I guess what you mean is:
Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).
To subtract -2x^2+4x-1 from 6x^2+3x-9, that is
6x^2+3x-9 - (-2x^2+4x-1). This can be written as
6x²+3x-9 - (-2x²+4x-1)
Now, opening the bracket, we will get
6x²+3x-9 +2x²-4x+1
Then, collecting like terms, we get
6x²+2x²+3x-4x-9+1
6x²+2x² = 8x²
3x-4x = -x
-9+1 = -8
∴6x²+2x²+3x-4x-9+1 becomes
8x²-x -8
The answer is 8x²-x -8.
We'll take out LCM of 24 seconds and 28 seconds.
that is, 168 seconds.
That means,
Car A and Car B will be side by side to each other after 2 mins 48 seconds after start.
<span>
It is easy the left side as to be ten times greater then your
right side for example my ones place is ten times greater my tens place
is ten times greater than my hundreds place and my hundreds place is ten
times greater than my thousands place i hope this will help you bye
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