The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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Answer: The 2 answers are inequality form and interval notation: n>200, and (200, ∞).
Step-by-step explanation: To solve for n, you’ll need to simplify the both sides of the inequality, and then isolating the variable.
Answer:
87
Step-by-step explanation:
If you look at the numbers upside down they are 86, 88, 89, 90 and 91 so the number that is covered by the car is 87.
Answer:
14
Step-by-step explanation:
70
1 * 70
5 * 14
7 * 10
42
1 * 42
3 * 14
7 * 6
28
1 * 28
2 * 14
7 * 4
pick the largest factor from 70 and check it they also work with the other two. 14 is the GCF.
