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2 years ago

Which expression is equivalent to One-fifth (150 x minus 80 y + 50 minus 50 x minus 25 y + 20)?

Mathematics

2 answers:

nekit [7.7K]2 years ago

5 0

Answer:

150 x - 80 y + 50 - 50 x - 25 y + 20

Arranging like terms 

150 x - 50 x -25 y - 80y + 50 + 20

100x - 105 y + 70

Doss [256]2 years ago

3 0

Answer:

20x - 21y + 14

Explanation:

$\rightarrow \sf \dfrac{1}{5} (150x - 80y + 50 - 50x - 25y + 20)$

collect like terms

$\rightarrow \sf \dfrac{1}{5} (150x-50x - 80y -25y + 50 + 20)$

add/subtract like terms

$\rightarrow \sf \dfrac{1}{5} (100x - 105y+70)$

distribute inside parenthesis

$\rightarrow \sf \dfrac{1}{5} (100x) + \dfrac{1}{5}( - 105y) + \dfrac{1}{5}(70)$

simplify the following

$\rightarrow \sf 20x -21y + 14$

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Which equation has the solutions X=1 +-SQRT 5?

Vesna [10]

Answer:

D is correct. $x^2-2x-4=0$

Step-by-step explanation:

We are given the root of the equation

$x=1+\pm \sqrt{5}$

If we are given solution of the equation then find equation using formula.

If a and b are the solution of equation then equation would be (x-a)(x-b)=0

Here, $a=1+\sqrt{5} , b=1-\sqrt{5}$

Equation form would be $(x-1-\sqrt{5})(x-1+\sqrt{5})=0$

Now we simplify the above equation to get correct option.

$x^2-x+x\sqrt{5}-x+1-\sqrt{5}-x\sqrt{5}+\sqrt{5}-5=0$

$x^2-2x-4=0$

So, D is correct. $x^2-2x-4=0$

8 0

3 years ago

Read 2 more answers

The following map shows the time it takes to drive between four cities in Texas. Jacob has to drive from San Antonio to Houston,

sertanlavr [38]

Answer:

it is 7 5/12

Step-by-step explanation:

3 and 1/3 plus 4 and 1/12 and you need to multiply the denominator to get 12 ( witch is 4 ) then multiply the numerator by 4 and then you add the 2 numbers together to get 4/12 + 1/12 and then you need to add the whole numbers 3 + 4

witch gets you 7 and 5/12

3 0

2 years ago

The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func

katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle ( $\frac{1}{3},\frac{1}4$ ).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A( $\frac{1}{3},\frac{1}4$ )

Let O be the origin i.e. (0,0)

Point B will be ( $\frac{1}{3},0$ )

Now, let us consider the right angled triangle $\triangle OBA$ :

Sides:

$Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}$

Using Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}$