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Elenna [48]
2 years ago
15

Which expression is equivalent to One-fifth (150 x minus 80 y + 50 minus 50 x minus 25 y + 20)?

Mathematics
2 answers:
nekit [7.7K]2 years ago
5 0

Answer:

150 x - 80 y + 50 - 50 x - 25 y + 20

<em><u>Arranging </u></em><em><u>like </u></em><em><u>terms </u></em>

150 x - 50 x -25 y - 80y + 50 + 20

100x - 105 y + 70

<h3>5 ( 20x - 21y + 14) </h3>
Doss [256]2 years ago
3 0

Answer:

20x - 21y + 14

Explanation:

\rightarrow \sf \dfrac{1}{5} (150x - 80y + 50 - 50x - 25y + 20)

collect like terms

\rightarrow \sf \dfrac{1}{5} (150x-50x - 80y -25y + 50  + 20)

add/subtract like terms

\rightarrow \sf \dfrac{1}{5} (100x - 105y+70)

distribute inside parenthesis

\rightarrow \sf \dfrac{1}{5} (100x) +  \dfrac{1}{5}( - 105y) +  \dfrac{1}{5}(70)

simplify the following

\rightarrow \sf 20x -21y +  14

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3 years ago
Can someone help me out on this please having trouble on both and show work please !!
inysia [295]

The difference of the expression is as follows:

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5) = - 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4) = x - 19

<h3>How to find the difference of the expression?</h3>

The difference of the expression can be found when we combine the like terms.

Therefore,

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5)

6y⁴ + 3y² - 7  - 12y⁴ + y² - 5

6y⁴ - 12y⁴ + 3y² + y² - 7 - 5

- 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4)

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3x - 2x - 15 - 4

x - 19

learn more on expression here: brainly.com/question/14294918

#SPJ1

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