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Elenna [48]
2 years ago
15

Which expression is equivalent to One-fifth (150 x minus 80 y + 50 minus 50 x minus 25 y + 20)?

Mathematics
2 answers:
nekit [7.7K]2 years ago
5 0

Answer:

150 x - 80 y + 50 - 50 x - 25 y + 20

<em><u>Arranging </u></em><em><u>like </u></em><em><u>terms </u></em>

150 x - 50 x -25 y - 80y + 50 + 20

100x - 105 y + 70

<h3>5 ( 20x - 21y + 14) </h3>
Doss [256]2 years ago
3 0

Answer:

20x - 21y + 14

Explanation:

\rightarrow \sf \dfrac{1}{5} (150x - 80y + 50 - 50x - 25y + 20)

collect like terms

\rightarrow \sf \dfrac{1}{5} (150x-50x - 80y -25y + 50  + 20)

add/subtract like terms

\rightarrow \sf \dfrac{1}{5} (100x - 105y+70)

distribute inside parenthesis

\rightarrow \sf \dfrac{1}{5} (100x) +  \dfrac{1}{5}( - 105y) +  \dfrac{1}{5}(70)

simplify the following

\rightarrow \sf 20x -21y +  14

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Which equation has the solutions X=1 +-SQRT 5?
Vesna [10]

Answer:

D is correct. x^2-2x-4=0

Step-by-step explanation:

We are given the root of the equation

x=1+\pm \sqrt{5}

If we are given solution of the equation then find equation using formula.

If a and b are the solution of equation then equation would be (x-a)(x-b)=0

Here, a=1+\sqrt{5} , b=1-\sqrt{5}

Equation form would be (x-1-\sqrt{5})(x-1+\sqrt{5})=0

Now we simplify the above equation to get correct option.

x^2-x+x\sqrt{5}-x+1-\sqrt{5}-x\sqrt{5}+\sqrt{5}-5=0

x^2-2x-4=0

So, D is correct.  x^2-2x-4=0

8 0
3 years ago
Read 2 more answers
The following map shows the time it takes to drive between four cities in Texas. Jacob has to drive from San Antonio to Houston,
sertanlavr [38]

Answer:

it is 7 5/12

Step-by-step explanation:

3 and 1/3 plus 4 and 1/12 and you need to multiply the denominator to get 12 ( witch is 4 ) then multiply the numerator by 4 and then you add the 2 numbers together to get 4/12 + 1/12 and then you need to add the whole numbers 3 + 4

witch gets you 7 and 5/12

3 0
2 years ago
The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func
katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle (\frac{1}{3},\frac{1}4).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A(\frac{1}{3},\frac{1}4)

Let O be the origin i.e. (0,0)

Point B will be (\frac{1}{3},0)

Now, let us consider the right angled triangle \triangle OBA:

Sides:

Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}

Using Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}

sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}

cos\angle AOB = \dfrac{Base}{Hypotenuse}

\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}

tan\angle AOB = \dfrac{Perpendicular}{Base}

\Rightarrow tan\angle AOB = \dfrac{3}{4}

cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}

\Rightarrow cosec\angle AOB = \dfrac{5}{3}

sec\angle AOB = \dfrac{Hypotenuse}{Base}

\Rightarrow sec\angle AOB = \dfrac{5}{4}

cot\angle AOB = \dfrac{Base}{Perpendicular}

\Rightarrow cot\angle AOB = \dfrac{4}{3}

3 0
3 years ago
which a and b family both have 8 people in there family. The ages of each term is listed below which which state meant is correc
Gwar [14]

Answer:

Family a because it is more chronological

Step-by-step explanation:

4 0
3 years ago
A single serving of jello requires 1/8 cups of sugar. How much sugar is needed for 6 servings?
sp2606 [1]
Hi there!

3/4 of sugar is needed for 6 servings.

1/8 x 6 = 6/8 simplify it and you get 3/4.

So 3/4 is your answer.

Hope this helps ;D
7 0
3 years ago
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