Find the area of the parallelogram with vertices k(1, 2, 2), l(1, 5, 3), m(3, 11, 3), and n(3, 8, 2).
Reil [10]
On examining the sides of the parallelogram, we see that the side KL lies in the plane x=1, and the side MN lies in the plane x=3.
Hence the height of the parallelogram is h=(3-1)=2.
The length of side mKL=sqrt((5-2)^2+(3-2)^2)=sqrt(3^2+1^2)=sqrt(10)
The length of side mMN=sqrt((11-8)^2+(3-2)^2)=sqrt(3^2+1^2)=sqrt(10)
Therefore the area of the parallelogram is mKL*h = sqrt(10)*2 = 2sqrt(10)
Answer: Area of parallelogram =
So you know the new equation must have the same slope as the old equation since they're parallel to one another. Next just simply take the slope and the point given and plug them into the point-slope formula and you have your new equation:
y-y1=m(x-x1) --- Point-Slope Formula
y+5=2(x-4)
y+5=2x-8
y=2x-13 --- Answer
Answer:
puedes buscar aplicasuinee que te solucionana estos problemas en play stor se llamaba mathwat o algo así, te responde tus trabajos
I think 15-3+4 is equivalent to 6+9-3+4
Answer:
x=6 ; y=1
Step-by-step explanation:
Let 'y' stand for the speed of the wind and 'x' stand for the speed of Santa. We will use the general equation (distance)=(rate)(time) to write two equations from the given information:
With the wind:
35=(x+y)(5)
Against the wind:
35=(x-y)(7)
Now we have two equations and two unknowns so we can solve for x and y. We get:
x=6 miles/min
y=1 miles/min