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Kazeer [188]
3 years ago
5

What is y= -2/3x + 5 written in standard form?

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
8 0

2x + 3y = 15. (";  Multiply each term by 3 and simplify.

GaryK [48]3 years ago
6 0

1) the standar form of the  equation is  ax+by  = c, therefore, for  y = -2/3x+5, multiply by 3 the previous equation, and its result is  3y = -2x+15⇒ 3y +2x = 15

the final result is  2x+3y = 15

 

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If you Don't Know the answer don't answer I will give Brianilist IF CORRECT
Tasya [4]

Answer:

<em>Distance ⇒ 5 meters</em>

Step-by-step explanation:

If we are to name the point with which Patrick stands P, Eddie's point E remains 4 meters south such that Dustin ( D ) is 3 meters to the right;

This in fact forms a 90 degree triangles, a right triangle with legs provided to be 4 and 3 knowing Eddie's remains 4 meters south, Dustin 3 meters to the right. If we are to determine how far apart Patrick and Dustin are, this is the hypotenuse of the right angle triangle formed, and the length can be determine through Pythagorean Theorem;

4^2 + 3^2 = x^2, x ⇒ distance between Patrick and Dustin,

16 + 9 = x^2,

x^2 = 25,

<em>Distance ( x ) ⇒ 5 meters</em>

6 0
3 years ago
Read 2 more answers
How to solve this ?<br>​
beks73 [17]

Answer:

1350

Step-by-step explanation:

use binomial general term expression for (r+1)th term

get the power of x in terms of r.

equate the expression to -2 and solve for r.

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5 0
1 year ago
A child takes a nap averaging three hours and get an average of 12 hours of sleep at night . Nap time and night time sleep can e
algol13
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8 0
3 years ago
At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
In-s [12.5K]

The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

At tangent line, the point is horizontal with the x-axis therefore slope = dy / dx = 0

<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

x^2 + y^2 = 2 x + 2 y

x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

2x – 2 = 0

x = 1

 

To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

1^2 + y^2 = 2 * 1 + 2 y

y^2 – 2y + 1 – 2 = 0

y^2 – 2y – 1 = 0

Finding the roots using the quadratic formula:

y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

y = -1.828 , 3.828

 

<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

3 0
4 years ago
Pls helppppp 100 points!!
Deffense [45]

Answer:

D

Step-by-step explanation:

please the answer is D which is 35x - 35y + 25

5 0
3 years ago
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