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3 years ago

Is 1.36 a rational number or irrational number

Mathematics

2 answers:

elena-s [515]3 years ago

5 0

Answer:

No an irrational number

Step-by-step explanation:

An irrational number is a number that cannot be expressed as a fraction of two integers . -1.36 can be expresed as -136/100

rjkz [21]3 years ago

3 0

Answer:

Rational!

Step-by-step explanation:

Any number that can be written in fraction form is a rational number. This includes integers, terminating decimals, and repeating decimals as well as fractions. So, any terminating decimal is a rational number. Any decimal number that is repeating can be written in the form a/b with b not equal to zero so it is a rational number.

I hope this helps you understand what a rational number is! Have a wonderful day!

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valentinak56 [21]

Multiply 2/3 by 84 which is 56.

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If we sample from a small finite population without replacement, the binomial distribution should not be used because the event

seropon [69]

Answer:

5/4324 = 0.001156337

Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans so 100 - 60 = 40 are democrats).

We extract a random sample of 30 senators and we want to answer this question:

What is the probability that 10 senators in the sample are republicans (and of course, 30 - 10 = 20 democrats)?

The answer using the h-g distribution is:

$\large \frac{\binom{60}{10}\binom{100-60}{30-10}}{\binom{100}{30}}=\frac{\binom{60}{10}\binom{40}{20}}{\binom{100}{30}}$

Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

$\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}$

Now compute each combination separately:

$\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700$

and now replace the values:

$\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}$

and that is it.

If the decimal expression is preferred then divide the fractions to get 0.001156337

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3 years ago

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1. multiply the first term of each binomials together

2. multiply the out terms together.

3. multiply the inner terms together

4. multiply the last terms of each expression together

5. list the four results of FOIL in order

6. combine the like terms.

I hope this helps

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