The standard algorithm in the US (though this might not be the standard everywhere) is to add the digits in the ones place (carrying the 1 - which represents 10 - if their sum is 10 or more), then to move to the tens place and add the digits there (again carrying the one if their sum is more than 10 - though in this case the one that represents 100) and then we move to the hundreds place and so on.
So, let's do this with the numbers given. 57+58. We would line these up one over the other so that the digits 8 and 7 which are in the ones place are above each other. We add these and get 15 which is one ten and five ones. The 5 gets put down and the 1 gets carried over. Now we focus on the digits in the tens place (here 5 and 5). We add these and to their sum add the 1 we carried. This gives us 11 (but in actuality it means 110). We bring down the leftmost 1 and carry the other. There are no digits in the hundreds place so we being down the 1 we carried earlier.
This gives us an answer of 115.
Answer:
JLK angle (I'm not 100% sure)
Answer:
$6.96
Step-by-step explanation:
0.25 pound = $1.74
for 1 pound multiply by 4, since there are four 0.25 (quarters) to 1 pound.
1.74*4 = 6.96
Answer:
x = 7
Step-by-step explanation:
See the attached figure.
As shown: A C D F is a trapezoid and BE is a mid-segment.
The mid-segment of the trapezoid is the average of its bases.
BE = 0.5 ( A F + C D)
Given: CD = 18 , BE = 2x + 10 and A F = 6x - 12
So,
2x + 10 = 0.5 ( 18 + 6x - 12)
Solve for x
2x + 10 = 0.5 (6 + 6x)
2x + 10 = 3 + 3x
10 - 3 = 3x - 2x
∴ x = 7
<u>So, the value of x is 7</u>
