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IrinaVladis [17]
3 years ago
8

If a square is 12 cm in length and 2 cm wide, what is the area of the square?

Mathematics
2 answers:
avanturin [10]3 years ago
5 0

Answer:

Squares have equal sides.

Sindrei [870]3 years ago
5 0
The shape would not be a square. But if you’re looking for an answer for those measurements then the answer will be 24 cm squared. Hope this helps!
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If John pays $144 for 9 pounds of pears, how much is each pound
Artist 52 [7]

Answer:

$16 per pound

Step-by-step explanation:

We want to find the price per pound.

Therefore, we must divide the cost by the pounds.

\frac{cost}{pounds}

We know it costs $144 for 9 pounds of pears. Therefore, $144 is the cost and there are 9 pounds.

\frac{\$144}{9 pounds}

Divide.

\$16 /pound

It costs $16 for each pound of pears.

5 0
3 years ago
Read 2 more answers
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
So, I'm completely lost on this. It's very easy to figure out as it's just writing a function, but I'm not entirely sure about t
Schach [20]
Width = w
length = w+2

f(w) =w(w+2) = w^2 + 2w.

Please, let me know whether the procedure is clear for you.

The answer is f(w)=w^2 + 2w.
8 0
3 years ago
What 5 divided by 475
Nataly [62]

Answer:

it's 0.01 (approx.)

Step-by-step explanation:

brainliest plz

8 0
2 years ago
Read 2 more answers
mia wants to earn 2500 in her job at a bycicle store she is paid 55 for every bycicle she tunes up the minimum number of bycicle
Thepotemich [5.8K]
Answer: 46

Explanation: If Mia is paid $55 for every bicycle, she would need to fix up/sell 46 bicycles. This is because 45 x 55 = 2475 and Mia wants over 2500 but 46 x 55 = 2530. Therefore, 46 is the minimum number of bicycles.
5 0
3 years ago
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