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IrinaVladis [17]
3 years ago
8

If a square is 12 cm in length and 2 cm wide, what is the area of the square?

Mathematics
2 answers:
avanturin [10]3 years ago
5 0

Answer:

Squares have equal sides.

Sindrei [870]3 years ago
5 0
The shape would not be a square. But if you’re looking for an answer for those measurements then the answer will be 24 cm squared. Hope this helps!
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If a gas tank of a large truck holds 64 gallons of gas if the tank is 5/8 full how many gallons of gas is in truck
den301095 [7]
Find 5/8 of full
find 5/8 of 64
5/8 times 64/1=320/8=160/4=80/2=40
answer is 40 gallons in the trick right now
4 0
3 years ago
Can someone help me with this?
Roman55 [17]

Answer:

Step-by-step explanation:

We first need to figure out how much money Jackie has since Pilar has the same amount of money, but in different coins. Jackie has 24 dimes and 13 quarters, so the amount of money is $2.40 + $3.25 = $5.65; therefore, Pilar has $5.65 also. In order to determine how many nickels and quarters Pilar has, we have to have a system of equations. It's up to us to write the equations we need to solve this. The first equation has to do with the NUMBER of coins Pilar has, the second has to do with the VALUE of each coin. We know that Pilar has only nickels and quarters and that she has a total of 53 coins. So the NUMBER equation is

n + q = 53

The VALUE equation relates how much each coin is worth to the total amount of money it equals:

.05n + .25q = 5.65.

Go back to the first equation and solve it for either n or q. I solved it for n:

n = 53 - q

Plug this into the second equation in place of n now to get:

.05(53 - q) + .25q = 5.65 and

2.65- .05q + .25q = 5.65 and

.20q = 3 so

q = 15. This means that there are 15 quarters. If there are 15 quarters, then there are

n + 15 = 53 nickels and

n = 38 nickels.

7 0
3 years ago
How do you find the first five terms of a sequence defined recursively
Blizzard [7]
Interesting question. Good to know for computer science.
Suppose you have a function like 
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1

a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3

an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3 
a3 = 7

a4 = a3 + 3
a4 = 7 + 3
a4 = 10

a5 = a4+ 3
a5 = 10 + 3
a5 = 13

I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16

a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.

So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
6 0
3 years ago
Evaluate -5x^2 − 8x + 1 when x = -3.
Yakvenalex [24]

Hello.

Answer: 70

New equation: −5(−3^2)−(8)(−3)+1


How to get the answer:

(−5)(−9)−(8)(−3)+1

=45−(8)(−3)+1

=45−(−24)+1

=69+1

=70


Have  a nice day

7 0
3 years ago
A=20 cm<br> b=48 cm<br> What is the length of c?
Ainat [17]
The value of c is 52
8 0
3 years ago
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