Answer:
its b I'm pretty sure........
Answer: Answer A: Both classes have a range of 45
Step-by-step explanation:
above the two graphs we can see a number line ranging from 50-100
bellow that, we can see 2 box and whisker plots, one for second period and one for fourth period. the larger rectangular boxes show all the number results, the line in between them states the average result. Both lines have starting points at 55 and ending points at 100.
100-55=45 45 being the range. Since 2nd and 4th both share the same range answer A could possibly be correct
B is wrong because 2nd period has a median of 90
C is wrong because no periods have a median of 100
D is wrong because most of the students scored an 85+
conclusion: answer A is correct
Answer:
that is the ten thousands place
Step-by-step explanation:
If a line's slope is
, the slope of the perpendicular line is
in this case, the given line has a slope 4, which is 4/1, so the perpendicular line has a slope/gradient
There are 2001 items in that set.
So n(A) = 2001
We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1
where,
m = starting value
n = ending value
In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001
This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)
