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Romashka-Z-Leto [24]
3 years ago
10

Find three consecutive even integers such that their sum is 50 more than the largest integer

Mathematics
1 answer:
hram777 [196]3 years ago
4 0
This is how I'd solve it:

1st no. = 2x                (2x)+(2x+2)+(2x+4)=(2x+4)+50
2nd no. = 2x+2                                  6x+6=2x+54
3rd no. = 2x+4                                       4x=48
                                                                x=12

Substitute the x value, and your numbers are <u>24, 26, and 28</u>.  To check: their sum (78) is 50 more than the largest integer (28). 
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