9514 1404 393
Answer:
3433 m^2
Step-by-step explanation:
The total surface area is the sum of the end areas and the lateral area.
The end areas together are a circle of diameter 0.4 m and two rectangles that are 0.4 m by 0.55 m.
End areas = πr^2 + 2LW = 3.14(0.2 m)^2 + 2(0.4 m)(0.55 m)
= 0.1256 m^2 +0.44 m^2 = 0.5656 m^2
The perimeter of the end piece is half the circumference of a 0.4 m circle and three sides of a 0.4 m by 0.55 m rectangle.
P = (1/2)πd + 2L +W = 1/2·3.14·0.4 m + 2(0.55 m) + 0.4 m = 2.128 m
The lateral area of the mailbox is the product of its length and the perimeter of the end piece:
LA = PL = (2.128 m)(0.6 m) = 1.2768 m^2
Then the total surface area of the mailbox is ...
0.5656 m^2 + 1.2768 m^2 = 1.8424 m^2
__
The area of aluminum required for 1863 mailboxes is ...
1863 × 1.8424 m^2 ≈ 3433 m^2
About 3433 square meters of aluminum are needed to make these mailboxes.
Answer = <span><span><span><span>12<span>x3</span></span>−<span>7<span>x2</span></span></span>+<span>9x</span></span>−<span>2</span></span>
A=10x(15x)-p(4x)^2
A=150x^2-16px^2
A=(150-16p)x^2
Answer : C
the total commission (c) a sales associate receives if he sells 15 laptop computers (l)
Total commission = number of laptops * commission for each laptop
Total commission is c
number of laptops is 15
commission for laptop is l
C = 15 * I
So c= 15l
the commission for selling each computer is $39.95
c= 15l
c = 15 * 39.95 = 599.25
Answer:
Figure 1: 4
Figure 2: 8
Figure 3: 16
Figure 4: 20
Step-by-step explanation:
Go around each figure and count how many cube lengths it takes to go around.
