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3 years ago

15

One number is 1 less than a second number. Twice the second number is less than 4 times the first. find the smaller of the two n

umbers.

1 answer:

KATRIN_1 [288]3 years ago

5 0

The number should be bigger than 2( 3,4,5,6....)

1st number=(x-1)

2nd number = x

2x<4(x-1)

2x<4x-4

-2x< -4

-x<-2

x>2

Example it could be 3

2x3 < 4(3-1)

6<4x2

6<8

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How to solve this system of equal: x+y+z=1;x^2+y^2+z^2=1

swat32

There are infinitely many solutions.

Algebraically, we can eliminate $z$ and try to solve for $x,y$ :

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