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4 years ago

15

One number is 1 less than a second number. Twice the second number is less than 4 times the first. find the smaller of the two n

umbers.

1 answer:

KATRIN_1 [288]4 years ago

5 0

The number should be bigger than 2( 3,4,5,6....)

1st number=(x-1)

2nd number = x

2x<4(x-1)

2x<4x-4

-2x< -4

-x<-2

x>2

Example it could be 3

2x3 < 4(3-1)

6<4x2

6<8

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3 years ago

Given<br> mZAOC is a straight angle.<br> MZAOB = 8x + 51°<br> mZBOC = 6x - 25°<br> Find mZAOB=

Tatiana [17]

Answer:

∠ AOB = 139°

Step-by-step explanation:

Since AOC is a straight line then

∠ AOB + ∠BOC = 180° , that is

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3 years ago

What is the measure of KPN?

Debora [2.8K]

Answer:

angle KPN=95 degree

Step-by-step explanation:

angle KPN = angle JPO (because they are vertically opposite angles)

Now,

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angle JPO + 85 =180

angle JPO =180-85

angle JPO =95

since angle JPO is equal to KPN ,angle KPN is 95 degree

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3 years ago

The length of a line segment is 7. Its end points are (1, 3) and (k, 3). Solve for k. Is there more than one solution? Explain.

Brilliant_brown [7]

$Endpoints:\\\\A(1,3)\ and\ B(k,3)\\\\Formula\ for\ length\ of\ line:\\\\
|AB|=\sqrt{(x_b-x_a)^2+(y_b-y_a)^2}\\\\
|AB|=7\\\\7=\sqrt{(k-1)^2+(3-3)^2}\\\\
7=\sqrt{k^2-2k-1}\ \ |^2\\\\
49=k^2-2k-1
$ $49=k^2-2k-1\\\\
-k^2+2k+1+49=0\\\\
-k^2+2k+50=0\\\\ \Delta=b^2-4ac\\\\a=-1,\ b=2,\ c=50 \\\\\Delta=(2)^2-4*(-1)*50=4-=4+200=204\\\\ \sqrt{\Delta}=2\sqrt{51}$ $\\\\k_1=\frac{-b-\sqrt{\Delta}}{2a}\ \ k_1=\frac{-2-2\sqrt{51}}{2*(-1)}=1+\sqrt{51} \\\\\ or\ k_2=\frac{-b+\sqrt{\Delta}}{2a}\ \ k_1=\frac{-2+2\sqrt{51}}{2*(-1)}=1-\sqrt{51}$

5 0

3 years ago