3 years ago

Using altitude and hypotenuse to find the area of a right triangle

1 answer:

3 0

First use Pythagoras theorem to find the remaining length of the base.
Then multiply the base with the altitude and divide that by 2 and you'll get the area

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Find the area of the shaded region. Round the the nearest tenth.

Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = $\frac{\theta}{360^{\circ} }\pi r^2$

Area of sector = $\frac{123}{360} \times 3.14 \times (18.6)^2$

Area of sector = $371.157 m^2$

Area of triangle = $\frac{1}{2} \times a \times b \times Sin x$

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = $\frac{1}{2} \times 18.6 \times 18.6 \times Sin 123$

Area of triangle = $145.073 m^2$

So, Area of shaded region = Area of sector - Area of triangle

= $371.157 m^2-145.073 m^2$

= $226.084 m^2$

Hence the area of the shaded region is 226.084 sq.m.

5 0

3 years ago

Sum and difference of 5+2.3

professor190 [17]

Answer:

sum: 7.3 difference:2.7

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

I need help asap pllz help !!

swat32

Answer:

14/28

Step-by-step explanation:

14/28 reduces down to 1/2

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2 years ago

For a process, the average range for all samples was 5 and the process average was 25. If the sample size was 10, calculate UCL

alexira [117]

Answer:

8.885

Step-by-step explanation:

Given that :

Sample size, n = 10

The average range, Rbar for all samples = 5

The upper control limit, UCL for the R-chart is :

UCL L= D4Rbar

From the control chart constant table, D4 = 1.777

Hence,

UCL = 1.777 * 5

UCL = 8.885

The UCL for the R-chart is 8.885

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2 years ago

I’ll give you all my love and affection if you help me with this ASAP PLEASE ;)

Zinaida [17]

Answer:

(0,12)

Step-by-step explanation:

Plug 0 into y

7 0

2 years ago