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adell [148]
3 years ago
6

Combine the terms and write the answer as one logorithm. Please show work.

Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:ln(x^{\frac{1}{4}}y^{\frac{1}{2}}z^{\frac{2}{3}})

Step-by-step explanation:

Formula:

k\times ln(a)=ln(a^{k})

ln(a)+ln(b)=ln(ab)

ln(a)-ln(b)=ln(\frac{a}{b})

\frac{1}{4}\times ln(x)=ln(x^{\frac{1}{4}})

\frac{-1}{2}\times ln(x)=ln(x^{\frac{-1}{2}})

\frac{2}{3}\times ln(x)=ln(x^{\frac{2}{3}})

Working:

So,\frac{1}{4}ln(x)-\frac{1}{2}ln(y)+\frac{2}{3}ln(z)=ln(x^\frac{1}{4})-ln(y^\frac{-1}{2})+ln(z^\frac{2}{3})

=ln(\frac{x^\frac{1}{4}}{y^{\frac{-1}{2}} } )+ln(z^{\frac{2}{3}})

=ln(x^\frac{1}{4}}{y^{\frac{1}{2}}z^{\frac{2}{3} })

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4 years ago
A quantity b varies jointly with c and d and inversely with eWhen b is 18, c is 4, d is 9, and e is 6What is the constant of var
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Answer:

constant of variation = 3

Step-by-step explanation:

we know that b varies jointly with c and d

so:

b∝c∝d

and b varies inversely with e, so

b∝\frac{1}{e}

and i will call the constant of variation k, this way we can make an equation for b in the following form:

b=k\frac{cd}{e}

this satisfy that b varies jointly with c and d (if b increases, c and d also increase) and inversely with e (if b increases, e decreases)

we know that when b is 18, c is 4, d is 9, and e is 6:

b=18\\c=4\\d=9\\e=6

substituting this in our equation for b:

b=k\frac{cd}{e}\\ 18=k\frac{(4)(9)}{6}

and we solve operations and clear for the constant of variation k:

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

3/5 is greater than 1/4

(2/4 is equal to 2.5/5---that should give you a visual picture why)  

8/10 is greater than 3/5

3/5 multipled by 2 is 6/10

so, 6/10<8/10

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3 years ago
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Answer:

2a+3b

Step-by-step explanation:

There wouldn't be a simplfied answer or solution if you don't have a solution for either a or b or both. And they are not like terms, so you can't add them together.

So the answer is 2a + 3b.

I hope this helps!

Have a great day!

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3 years ago
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