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adell [148]
4 years ago
6

Combine the terms and write the answer as one logorithm. Please show work.

Mathematics
1 answer:
tankabanditka [31]4 years ago
6 0

Answer:ln(x^{\frac{1}{4}}y^{\frac{1}{2}}z^{\frac{2}{3}})

Step-by-step explanation:

Formula:

k\times ln(a)=ln(a^{k})

ln(a)+ln(b)=ln(ab)

ln(a)-ln(b)=ln(\frac{a}{b})

\frac{1}{4}\times ln(x)=ln(x^{\frac{1}{4}})

\frac{-1}{2}\times ln(x)=ln(x^{\frac{-1}{2}})

\frac{2}{3}\times ln(x)=ln(x^{\frac{2}{3}})

Working:

So,\frac{1}{4}ln(x)-\frac{1}{2}ln(y)+\frac{2}{3}ln(z)=ln(x^\frac{1}{4})-ln(y^\frac{-1}{2})+ln(z^\frac{2}{3})

=ln(\frac{x^\frac{1}{4}}{y^{\frac{-1}{2}} } )+ln(z^{\frac{2}{3}})

=ln(x^\frac{1}{4}}{y^{\frac{1}{2}}z^{\frac{2}{3} })

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