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lesya [120]
2 years ago
11

Can someone help pls.

Mathematics
2 answers:
kap26 [50]2 years ago
8 0

<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>

<em>I think, to start out, we could set up the problem like so</em>

<em>15 + t ≥ 26</em>

<em>because t is not a set number. </em>

<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>

<em>t ≥ 11</em>

<em>So the resulting answer is t ≥ 11.</em>

<em />

<em>I hope that my interpretation helps.</em>

<em>-Toremi</em>

<em />

LekaFEV [45]2 years ago
3 0

Answer:

Step-by-step explanation:

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charle [14.2K]
5(3√x)+9(3√x)
=3√x(5+9)
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answer is C. third choice 14(3√x)
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I have ₹355.50 in my pocket . i purchased a shirt for ₹ 235.50 and a pair of socks for ₹ 22.65. How much money is left with me n
Korolek [52]

Answer:

97.35

Step-by-step explanation:

355.5 - 235.5 -22.65

I am subtracting 235.5 and 22.65  from 355.5 because I am spending that much money on the things.

=> 355.5 - 235.5 - 22.65

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3 years ago
Suppose that $1,000 is deposited into an account that yields
Lana71 [14]
ANSWER : $1,215.51

P= Principal = $1000
R= rate = 5% = 0.05
N= number or periods in 1 year (1 time pre year)
T= time expressed in years = 4 years

A= P (1 + r/n) nxt
= 1,000 (1+ 0.05/1) 1x4
= 1,215.51

6 0
3 years ago
Please can someone help my assignment​
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

In ΔJOY and ΔLAF,

If ∠O ≅ ∠J

And \frac{JO}{AL}=\frac{YO}{FA}

Then ΔJOY ~ ΔLAF

By SAS property of similarity of two triangles.

(If two corresponding sides of the triangles are proportional and angles between these sides are equal)

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3 years ago
calculate the means and the standard deviation of the following set of data 4.578g, 4.581g, 4.572g, 4.573g, 4.601g, 4.577g. stat
AfilCa [17]

Answer:

68% Confidence interval  = [4.5752, 4.5848]

95% Confidence interval  = [4.5688, 4.5918]

Step-by-step explanation:

Sample mean (X) = 4.580

Sample Standard Deviation (S) = 0.01065

Sample size (n) = 6

T_{(5)} for alpha/2 0.84 = 1.1037

T_{(5)} for alpha/2 0.975 = 2.5706

68% Confidence interval = [x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}] = [4.5752, 4.5848]

95% Confidence interval = [x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}] = [4.5688, 4.5918]

7 0
3 years ago
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