Can someone help pls.
2 answers:
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Student B is wrong , student A is correct in simplifying the expression .
Expression B must be simplified to cot θ .
Formulas to be used are :
1 - θ =
θ
1 - θ =
θ .
Since , location of error is step 3 , we will start from there
[ ( 1 - θ ) / sin θ ] / cos θ = [ ( 1 -
θ ) / sin θ ] * [ 1 / cos θ ]
= ( 1 - θ ) / ( sin θ * cos θ )
= θ / ( sin θ * cos θ )
= cot θ .
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Since , the question is incomplete we assume it to be :
Answer:
0.9192 = 91.92% probability that the weight will be less than 4473 grams.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean weight of 3950 grams and a standard deviation of 374 grams.
This means that
Find the probability that the weight will be less than 4473 grams.
This is the pvalue of Z when X = 4473. So
has a pvalue of 0.9192
0.9192 = 91.92% probability that the weight will be less than 4473 grams.