8: 20
9: 90
I am so sorry if this is wrong. I am not good at this type of things
Steps to solve:
3x+2y=-4
3x=-4-2y
x=- \frac{4}{3}- \frac{2}{3}y [/tex]
Answer:
a. A customer earns 1 free night per 10 nights stayed.
Step-by-step explanation:
The missing function is:
f(x) = x/10
The missing options are:
<em>
a. A customer earns 1 free night per 10 nights stayed. </em>
<em>
b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed.
</em>
<em>
c.A customer earns x – 10 free nights for every 10 nights stayed. </em>
<em>
d. A customer earns 10 free nights after x number of nights stayed.
</em>
The function means that after a customer stayed 10 nights, a free night is earned. That is, replacing x = 10 into the function, we get:
f(10) = 10/10 = 1
which means 10 nights are equivalent to 1 free night.
Supplementary angles sum up to 180°, suppose the supplement of 161° is x. Then
161+x=180
solving for x we subtract 161 from both sides
161-161+x=180-161
x=19
thus the supplement is 19°
The tank with Chemical X "takes up" a space of 25ft³. Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume. The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:

To find the volume of a cylinder, we find the base area and multiply by the height. We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:

We would now divide both sides by 3 2/10:

This is the same as:

So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.