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rosijanka [135]
3 years ago
11

Define the following propositions: .p: You drive over 65 miles per hour q You get a speeding ticket Translate the following Engl

ish sentence into logical expressions using the definitions above (a) You drive over 65 miles per hour, but you do not get a speeding ticket. (b) If you do not drive over 65 miles per hour, then you will not get a speeding ticket (c) You get a speeding ticket, but you did not drive over 65 miles per hour.
Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

Answer:

a.p→¬q

b.¬p→¬q

c.q→¬p

Step-by-step explanation:

p:You drive over 65 miles per hour

¬p: <em>You do not drive over 65 miles per hour</em>

q:You get a speeding ticket

¬q:<em>You do not get a speeding ticket</em>

(a) You drive over 65 miles per hour, but <em>you do not get a speeding ticket</em>

the first sentence is p and because the consequence is the opposite of q then is no q

p→¬q

(b) If you do not drive over 65 miles per hour, then you will not get a speeding ticket

The first sentence is the opposite of p (¬p), and the second sentence is the opposite of q

¬p→¬q

(c) You get a speeding ticket, but you did not drive over 65 miles per hour.

The first one is q, and the second one is the opposite of p so

q→¬p

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Which of the following statements is false?
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Option D

The sum of two irrational numbers is always rational is false statement

<em><u>Solution:</u></em>

<h3><u>The sum of two rational numbers is always rational</u></h3>

"The sum of two rational numbers is rational."

So, adding two rationals is the same as adding two such fractions, which will result in another fraction of this same form since integers are closed under addition and multiplication. Thus, adding two rational numbers produces another rational number.

For example:

\frac{1}{4} + \frac{1}{5} = \frac{9}{20}

rational number + rational number = rational number

Hence this statement is true

<h3><u>The product of a non zero rational number and an irrational number is always irrational</u></h3>

If you multiply any irrational number by the rational number zero, the result will be zero, which is rational.

Any other situation, however, of a rational times an irrational will be irrational.

A better statement would be: "The product of a non-zero rational number and an irrational number is irrational."

So this statement is correct

<h3><u>The product of two rational numbers is always rational</u></h3>

The product of two rational numbers is always rational.

A number is said to be a rational number if it is of the form p/q,where p and q are integers and q ≠ 0

Any integer is a rational number because it can be written in p/q form.

Hence it is clear that product of two rational numbers is always rational.

So this statement is correct

<h3><u>The sum of two irrational numbers is always rational</u></h3>

"The sum of two irrational numbers is SOMETIMES irrational."

The sum of two irrational numbers, in some cases, will be irrational. However, if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational.

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2 years ago
What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
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Answer:

f(x)=-\frac{1}{8}(x-3)^2+3

Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

(x-h)^2=4p(y-k), where (h,k) is the vertex of the parabola.


The axis of this parabola meets the directrix at (3,5).

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


h=\frac{3+3}{2}=3 and k=\frac{5+1}{2}=3.


The equation of the parabola now becomes,


(x-3)^2=4p(y-3).


Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


(x-3)^2=4(-2)(y-3).


(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









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