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allochka39001 [22]

3 years ago

5

In Kim's class 5 times as many students take the bus as those who walk. A total of 24 students walk or take rhe bus. How many mo

re students take the bus than walk

1 answer:

nataly862011 [7]3 years ago

3 0

Hmm Lemme Think I Will Have A Answer Later Thank You

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PLS HELP I WILL GIVE BRAINLIEST

drek231 [11]

Answer:

(0, -10)

Step-by-step explanation:

If you add both together from x - y, each add up to their own value. For example, -5, and -9 would be -14. It's quite simple. I hope this helps. I'm sorry if this is not what you are looking for.

4 0

2 years ago

Kiara and Mia went to a county fair. They each paid the same admission fee but they were in a different number of rides. Each ri

aliya0001 [1]

let's take admission fee= z

8z+11z=17.50+21.25

19z=38.75

z=38.25/19

z=2.4 (aprox)

Or In case of Kiara 17.50 amount paid in 8 rides

.so 1 ride=17.50/8

=2.1875

same In case of mia

so 1 ride=21.25/11

=1.9318.

but, they are not match so there is problem in your Questions.

6 0

2 years ago

Mr. Vazquez determines that the area of a bathroom in his house is 25 square feet less than 1/5 of the area of the living room.

kozerog [31]

Answer is 300 square feet

5 0

3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

Explain how to correctly find the missing side

kotegsom [21]

Pythagorean Theorem

a² + b² = c²

c = 13

a = 4

(Missing side) = b

4² + b² = 13²

16 + b² = 169

16 - 16

169 - 16 = 153

Square Root of 153 = 12.369

b = 12.369

The missing side is 12.369 (rounded to 12 as a whole number)

6 0

2 years ago

Read 2 more answers