Answer:
PQ = 3.58, and RQ = 10.4
Step-by-step explanation:
We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.
Hypotenuse = 11,
Opposite side is PQ
Adjacent side is RQ
x = 19
Sin x = (opposite side)/(hypotenuse)
Cos x = (adjacent side)/(hypotenuse)
For PQ, this is the side opposite to the angle, so use sin,
Sin 19 = x/11
11(Sin 19) = x
3.58 = x (rounded to the nearest hundredth)
For RQ, this is the side adjacent to the angle, so use cos,
Cos 19 = x/11
11(Cos 19) = x
10.4 = x (rounded to the nearest hundredth)
Answer:
your mom
Step-by-step explanation:
lol
Answer:
P(A)=0.55
P(A and B)=P(A∩B)=0.1265
P(A or B)=P(A∪B)=0.7635
P(A|B)=0.3721
Step-by-step explanation:
P(A')=0.45
P(A)=1-0.45=0.55
P(B∩A)=?
P(B|A)=0.23
P(B|A)=(P(A∩B))/P(A)
0.23=(P(A∩B))/0.55
P(A∩B)=0.23×0.55=0.1265
P(A∪B)=P(A)+P(B)-P(A∩B)
=0.55+0.34-0.1265
=0.7635
P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721
Answer:
Result:
Step-by-step explanation:
Given
The parallelogram DEFG
DE = 6x-12
FG = 2x+36
EF = 4y
DG = 6y-42
We know that the opposite sides of a parallelogram are equal.
As DE and FG are opposite sides, so
DE = FG
substituting DE = 6x-12 and FG = 2x+36 in the equation
6x-12 = 2x+36
6x-2x = 36+12
simplifying
4x = 48
dividing both sides by 4
4x/4 = 48/4
x = 12
Therefore,
The value of x = 12
Also, EF and DG are opposite sides, so
EF = DG
substituting EF = 4y and DG = 6y-42 in the equation
4y = 6y-42
switching sides
6y-42 = 4y
6y-4y = 42
2y = 42
dividing both sides by 2
2y/2 = 42/2
y = 21
Therefore,
The value of y = 21
Result:
Answer:
56
Step-by-step explanation:
