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IgorLugansk [536]
3 years ago
5

Help me answer the question.

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0
1/8 = 12.5 and 3/4 = 75 so he can wash 6 times before running out.
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One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
Point R is located on segment QS. If QR = 10 and RS = 7, what is the measure of QS?
Vadim26 [7]

Answer:

QS = 17 units

Step-by-step explanation:

Given:

R located at QS

QR = 10

RS = 7

Find:

Measure of QS

Computation:

QS = QR + RS

QS = 10 + 7

QS = 17 units

6 0
3 years ago
What's the exact value for this trigonometric function sin 60 degrees
Elodia [21]
\sin60^\circ=\dfrac{\sqrt{3}}{2}
3 0
3 years ago
**
EastWind [94]

Answer: A,C

Step-by-step explanation: They are facing each other making them interior angles

6 0
3 years ago
PLEASE HELP ME
omeli [17]

Step-by-step explanation:

it will take you 15 minutes

7 0
3 years ago
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