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V125BC [204]
3 years ago
12

Can you solve this for me please​

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

Graph 1

Step-by-step explanation:

f(x) = __

In this equation (f(2) = 4) the 2 is the x value. All this question is asking is which graph shows a y value of 4 when x is 2.

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Bill is a used car salesman. He sells a used automobile for $15,799. If he receives a 4%
Scrat [10]

Answer: 4 cents or .4

Step-by-step explanation:

Whenever in a problem like this where there is a fee, tax, and or bonus you move the decimal in front of the number and round to the nearest penny but if there is only one number in front of the decimal you don’t gotta do anything with it unless its .5 or higher but .4 and below you keep the same.

7 0
3 years ago
Which graph is the graph of f(x) = -3|x+2|?
nata0808 [166]
The 3rd one because you have to get the y-intercept also which is -6
4 0
4 years ago
Read 2 more answers
Find the value of x<br> PLEAASEEE HELP!!!
vodomira [7]

Answer:

x = 37

Step-by-step explanation:

4x + 3 + x - 8 = 180

4x + x - 8 + 3 = 180

5x - 5 = 180

5x = 185

x = 37

Hope this helps!

7 0
3 years ago
If it took 28 minutes to run 4 miles, then at that rate, how long would it take to run 20 miles?
SSSSS [86.1K]

Answer:

140 minutes

Step-by-step explanation:

After 28 mins you've gone 4 miles, assuming this rate is constant and you dont slow down or speed up, in order to get to 20 miles you will have run 5x as much (20/4 = 5), thus 5x the amount of time (28x5).

20/4 = 5

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8 0
3 years ago
Read 2 more answers
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
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