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pickupchik [31]
3 years ago
5

A lamina occupies the disk x squared space plus space y squared space less or equal than 4. Find the mass, if the density at any

point is proportional to its distance from the origin, where the proportionality constant is 3.

Mathematics
1 answer:
Bingel [31]3 years ago
4 0

Answer: Mass of Lamina is (K/3)

Centre of mass is (3/8, 3pi/16)

Step-by-step explanation:

Find explanation in the attachments

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It’s A) 9.1 because it equals 82.81 while answer B) 9.2 equals 84.64.
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3 years ago
Expand to write an equivalent expression:<br> -1/4(-8x+12y)
Iteru [2.4K]

Answer:

2x-3y

Step-by-step explanation:

-1/4×-8x= 8/4x = 2x

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7 0
3 years ago
The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers
Airida [17]

Answer:

a) P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)

P(Z>2.357)=1-P(Z

b) P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)

P(Z

c)  

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

P(-1.179Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where \mu=3 and \sigma=\sqrt{9}=3

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z>2.357)=1-P(Z

Part b

P(\bar X  \frac{2.5-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z

Part c

For this case we want this probability:

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

And using a calculator, excel or the normal standard table we have that:

P(-1.179

7 0
3 years ago
√x&lt;4 A.20 B.12 C.2 D.-1 E.5. F. No solution
evablogger [386]
We know that for √x to be meaningful, we must have x ≥ 0.

If we square both sides of the inequality, we have
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Thus the whole solution is
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5 0
3 years ago
Paul, Joey, and Matt have to catch the train back to school at 5:00pm. They want to tour the air and space museum for 1 hour and
Zigmanuir [339]

Answer:

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Amount of time to save  = 20min

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So;

Total time  = 2hr 35min

So;

        5pm - 2hr 35min  = 2:25pm

3 0
3 years ago
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