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mihalych1998 [28]
3 years ago
10

Find the third, fourth, and fifth terms of the sequence defined by

Mathematics
2 answers:
statuscvo [17]3 years ago
7 0

By the recursive definition,

a_3=2a_2-a_1=2\cdot9-4=14

a_4=2a_3-a_2=2\cdot14-9=19

a_5=2a_4-a_3=2\cdot19-14=24

a_6=2a_5-a_4=2\cdot24-19=29

olga_2 [115]3 years ago
7 0

Answer:

  a3=14, a4=19, a5=24

Step-by-step explanation:

Put the numbers where the symbols are and do the arithmetic.

  a3 = 2(a2) -(a1) = 2(9) -4 = 14

  a4 = 2(a3) -(a2) = 2(14) -9 = 19

  a5 = 2(a4) -(a3) = 2(19) -14 = 24

  a6 = 2(a5) -(a4) = 2(24) -19 = 29

_____

With a little work, you can show that this is an arithmetic sequence with a common difference of a2-a1 = 5.

Let d = a[2] -a[1]

Of course, the second term is that difference added to the first:

  a[2] = a[1] + (a[2] -a[1]) = a[1] +d

The third term is ...

  a[3] = 2a[2] -a[1] = a[2] +(a[2] -a[1]) = a[2] +d

  a[4] = 2a[3] -a[2] = a[3] +(a[3] -a[2]) = a[3] -(a[2] +d) -a[2] = a[3] +d

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\bf m_{yx}=\frac{(\sum y)(\sum x)^2-(\sum x)(\sum xy)}{n\sum x^2-(\sum x)^2}

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<u>Note:</u> <em>Be careful not to confuse  </em>

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<h3>y = 176.6061x + 0.3591 </h3>

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\bf s_{yx}=\sqrt{\frac{(y-y_{est})^2}{n}}

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\bf s_{yx}=\sqrt{\frac{39515985}{10}}=1987.8628

Now, to find the line that relates x as a function of y, we simply switch the roles of x and y in the formulas.  

So now we have:

x as a function of y

(x=response variable, y=explanatory variable)

\bf x=m_{xy}y+b_{xy}

where

\bf m_{xy} is the slope of the line

\bf b_{xy} is the x-intercept

In this case we use these formulas:

\bf m_{xy}=\frac{(\sum x)(\sum y)^2-(\sum y)(\sum xy)}{n\sum y^2-(\sum y)^2}

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<u>Note:</u> <em>Be careful not to confuse  </em>

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