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3 years ago

7

A part of a line that starts at one endpoint and extends forever in one direction is a

2 answers:

Valentin [98]3 years ago

7 0

Answer:

Ray

Step-by-step explanation:

A pex

Alinara [238K]3 years ago

6 0

It is called a ray.
segments have two end points. and a ray has one end point ad extends forever in one direction, and a line extends forever in both directions.

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Simplify √49 + [√81 - x(9x = 14)]

eimsori [14]

$\longrightarrow{\green{- 9 {x}^{2} + 14x + 16}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$\sqrt{49} + [ \sqrt{81} - x \: (9x - 14) ] \\ \\ = \sqrt{7 \times 7} + [ \sqrt{9 \times 9} - 9 {x}^{2} + 14x] \\ \\ = \sqrt{( {7})^{2} } + [ \sqrt{ ({9})^{2} } - 9 {x}^{2} + 14x ] \\ \\ (∵ \sqrt{ ({x})^{2} } = x ) \\ \\ = 7 + (9 - 9 {x}^{2} + 14x) \\ \\ = 7 + 9 - 9 {x}^{2} + 14x \\ \\ = - 9 {x}^{2} + 14x + 16$

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3 years ago

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enot [183]

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4 years ago

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natka813 [3]

Answer:

The series is absolutely convergent.

Step-by-step explanation:

By ratio test, we find the limit as n approaches infinity of

|[a_(n+1)]/a_n|

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a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)

[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]

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3 years ago

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Answer:

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tino4ka555 [31]

Answer:

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