Answer:
The question is incomplete, it lacks the mRNA sequence. The sequence is as follows:
5′−AUGGCAAGAAAA−3′
The answer is Met-Ala-Arg-Lys
Explanation:
Gene expression in living organisms involves the process of transcription and translation. Transcription is the synthesis of a complementary strand of mRNA from a DNA template while translation involves using the transcibed mRNA as a template to synthesize amino acid sequence (proteins).
In the RIBOSOME, where the synthesis of protein occurs, the mRNA nuceleotide sequence is read in a group of three nucleotides called CODON. Each codon specifies a particular amino acid. The collection of all codons is the genetic code. Hence, for a specific mRNA sequence that reads 5′−AUGGCAAGAAAA−3′. The nucleotides will be read three at a time starting with AUG which is a codon that encodes METHIONINE.
Next, GCA is a codon that encodes ALANINE
Next, AGA is a codon that encodes ARGININE
Finally, AAA is a codon that encodes LYSINE.
Hence, the amino acid sequence using the above mRNA sequence, will read: Met-Ala-Arg-Lys
Answer:
The molecule on the right; the middle carbon is asymmetric
Explanation:
Answer: No sé la respuesta, hablo inglés, solo estoy usando el traductor de Google y solo quiero puntos Jajaja
Most carbon atoms have about 4 bonding in them.
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