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3 years ago

Seven prepsters each have 1/2 of a cady bar, how many candy bars do they have in all

Mathematics

2 answers:

grigory [225]3 years ago

7 0

In total the all have 4 1/2 candy bars.

madam [21]3 years ago

3 0

7×1/2=7/2 or 3 1/2. As a result, they have total 3 1/2 candies. Hope it help!

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Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p

posledela

Answer:

P=0.0000037

P=0.00037%

Step-by-step explanation:

Probability

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

$\displaystyle \frac{4}{52}=\frac{1}{13}$

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

$\displaystyle \frac{3}{51}=\frac{1}{17}$

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

$\displaystyle \frac{2}{50}=\frac{1}{25}$

Finally, the probability of getting the remaining ace out of the 49 cards is:

$\displaystyle \frac{1}{49}$

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

$\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}$

$\displaystyle P= \frac{1}{270,725}$

P=0.0000037

P=0.00037%

3 0

3 years ago

Solve f(x)=x²- x - 6

alexgriva [62]

Answer:

I hope one of these can help you find what you need

Step-by-step explanation:

8 0

3 years ago

Find the missing term in geometric sequence. 4,....,16

Sergeeva-Olga [200]

The answer is 8
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4 0

3 years ago

Read 2 more answers

You have made two of the exact same necklaces that cost you a total of $15 in supplies. You have chosen to mark up the price by

tatyana61 [14]

Answer:

A) The selling price for each necklaces is $8.625

B) The profit mark in each necklaces is 15%

Step-by-step explanation:

Given as :

The total cost of two necklaces = c.p = $15

The markup percentage for the necklaces = m = 15%

Let The selling price for both necklaces = s.p

A ) Now, From markup method

m% = $\dfrac{s.p - c.p}{c.p}$

or, 15% = $\dfrac{s.p - 15}{15}$

or, 15% = $\dfrac{s.p}{15}$ - 1

or, $\dfrac{s.p}{15}$ = 1 + 15%

or, $\dfrac{s.p}{15}$ = 1 + $\dfrac{15}{100}$

or, $\dfrac{s.p}{15}$ = $\dfrac{100 + 15}{100}$

or, $\dfrac{s.p}{15}$ = $\dfrac{115}{100}$

∴ s.p = $\frac{15\times 115}{100}$

I.e s.p = $17.25

So, selling price of two necklaces = s.p = $17.25

or, selling price of one necklaces = s.p = $\dfrac{17.25}{2}$ = $8.625

Hence, The selling price for each necklaces is $8.625

Now, Again

B) ∵ The total cost of two necklaces = c.p = $15

So, The cost price of one necklaces = $\dfrac{15}{2}$ = $7.5

∴ profit% for each necklace = $\dfrac{s.p - c.p}{c.p}$

i.e profit% for each necklace = $\dfrac{8.625 - 7.5}{7.5}$

Or, profit% for each necklace = $\dfrac{1.125}{7.5}$

Or, profit% for each necklace = 0.15

So, The profit make in each necklaces = 15%

Hence, The profit mark in each necklaces is 15%

Answer

8 0

3 years ago

A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele

arsen [322]

The shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

<h3>what will be the time in which the blocker will block the ball?</h3>

The given equation for ball height

$=6+30t-16t^{2}$

The equation for the blocker's height will be

$=9+25t-16t^{2}$

But, the shot is made before two-tenths of a second or 0.2 seconds therefore modified equation for ball height is

$=6+30(t-0.2)-16(t-0.2)^{2}$

Now for the shot to be blocked, the height of the shot-blocker must be greater than the height of the ball which is shot before 0.2 seconds :

$9+25t-16t^{2} \geq 6+30(t-0.2)-16(t-0.2)^{2}$

$9+25t-16t^{2} \geq6+30t-6-16(t^{2} -0.4t+0.04)$

$9+25t-16t^{2} \geq30t-16t^{2} -6.4t+0.64$

$9+25t\geq36.4t-0.64$

$9.64\geq11.4t$

$t \leq \dfrac{9.64}{11.4}=0.846$

Thus the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.

To know more about the Equation of motions follow

brainly.com/question/25951773

5 0

2 years ago