So I'm assuming that you're taking Calculus. The first thing you want to do is take the integral of f(x)... Use the power rule to get: 4X^2-13X+3. Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this) Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25 Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!) Plugging these value in for f(x), we get f(1)=2.833 f(3)=-8.5 f(4)=1.667 Thus X=1 is the max and X=3 is the min. So max:(1,2.833) min:(3,-8.5)
