The radius of a coin is 12 mm what is the diameter of the coin what is the circumference of the coin what is the area of the coi
1 answer:
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Answer: x ≈ 1.59688927, −1.60312387, −4.67045686, 4.69039614, 7.872914, −7.91513776, −10.89002194
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Simplify 2*cosx*(2x+30°) + √3=0
Simplify each term.
Apply the distributive property.
- 2 cos ( x ) ( 2 x ) + 2 cos ( x ) * 30 ° + √ 3 = 0
- Multiply 2 by 2
- 4 cos ( x ) x + 2 cos ( x ) *30 ° + √ 3 = 0
- Multiply 30 °by 2
- 4 cos ( x ) x + 60 cos ( x ) + √ 3 = 0
- Reorder factors in 4 cos ( x ) x + 60 cos ( x ) + √3
- 4xcos(x)+60cos(x)+√3=0
- Graph each side of the equation. The solution is the x-value of the point of intersection. x ≈ 1.59688927 , − 1.60312387 , − 4.67045686 , 4.69039614 , 7.872914 , − 7.91513776 , − 10.89002194
Answer:
See photo
Step-by-step explanation:
We can fill out many of these pretty easily. Look at the picture below. (Black numbers represent what information they already gave us)
Now, for the actual math.
If a total of 46 seventh-graders were surveyed and 28 seventh-graders spent more than an hour on their phone, then that means that there would have to be 46-28=18 students that spend less than an hour on their phone.
If there are 43 total students that spend more than an hour on their phone, and 28 of those are seventh-graders, then there are 43-28=15 eighth-graders that spend more than an hour on their phone
Then, if there are 27 total eighth-graders, and 15 of those spend more than an hour, then that leaves 27-15=12 eighth-graders that spend less than an hour on their phone.
Lastly, figure out the total numbers.
There are 18 seventh-graders and 12 eighth-graders that spend less than an hour on their phone, so there is a total of 18+12 = 30 students that spend less than an hour on their phone.
There are a total of 46 seventh-graders and 27 eighth-graders that were surveyed, which is a total of 73 students surveyed.
