Negative abscissa, zero ordinate is between Quadrant II and Quadrant III.
Hope this helps! :)
Answer:
6xy²+7-x²y²-5x²y+3x²y²=6x²+7+2x²y²-5x²y
Answer:
Step-by-step explanation:
We want to find the inverse of the function:
To find the inverse of a function, we will flip the variables and solve for <em>y</em>. So:
Solve for <em>y</em>. Subtract two from both sides:
Divide both sides by two:
And take the principal square root of both sides. Therefore:
Answer:
No
Step-by-step explanation:
No. You can see why if you remove the brackets.
y=x^2 - 3x.
A linear function must have x and y with powers of 1. Also it can't something like x^2 - y^2 = 5
x^2 - y^2 = 0 is the only exception I can think of, but that really is a system of equations. If you graph it. you get two equations which cross at 0 and nowhere else.
Answer:
15x+5+22x+4+60=180
37x=180-60-5
37x=115
x=115/37
x=3
angle b
22*3+4=70°
angle c
15*3+5=50°
have a nice day . hope this helps