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alex41 [277]
3 years ago
6

PLEASE HELP!!! PLATO ALGEBRA 2

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

(gof) (4) = 9

Hence, option A is true.

Step-by-step explanation:

f(x)=-x³

g(x)=|1/8x -1|

(gof) (4) = g{f(4)}

First wee need to determine f(4)

f(4)=-(4)³

    = -64

so

  (gof) (4) = g{f(4)} = g(-64)

                             =  \left|\frac{1}{8}\left(-64\right)-1\right|

                             =\left|-\frac{1}{8}\cdot \:64-1\right|

                             =\left|-8-1\right|

                             =\left|-9\right|

\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a

                             =9        

Thus,

(gof) (4) = 9

Hence, option A is true.

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Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

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Answer:

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Step-by-step explanation:

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4/9*13=q

this gives you

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Read 2 more answers
Given Triangle DEF is isosceles and angle D is the vertex angle, Find x, DE, DF, EF
ch4aika [34]

Answer:

x=2;DE,EF=9,DF=5

Step-by-step explanation:

Since DEF is isoceles, you can set the equations

x+7 and 2x+5 equal to each other

x+7=2x+5, now solve for x

-x=-2,

x=2, now plug in for each side

DE,EF=9

DF=3(2)-1=5

4 0
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