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Katena32 [7]
3 years ago
6

A bag has five red marbles, six blue marbles, and four black marbles. What is the probability of picking a blue marble, replacin

g it, and then picking another blue marble?
a)1/15
b)8/75
c)4/25
d)1/9
Mathematics
2 answers:
love history [14]3 years ago
7 0
5 red, 6 blue, 4 black...total of 15

P(picking blue) = 6/15 ...reduces to 2/5
replacing
P(picking blue) = 6/16...reduces to 2/5

P(both) : 2/5 * 2/5 = 4/25 <==


Anit [1.1K]3 years ago
3 0

Answer:

4/15 is 100% the answer *NOT* 1/9 or anything else!

Step-by-step explanation:

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I pretty sure x equals 3
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The top and bottom ends of a windshield wiper blade are R = 24 in. and r = 14 in., respectively, from the pivot point. While in
Orlov [11]

Answer:

Area swept by the blade = 448in^{2}

Step-by-step explanation:

The arc the wiper wipes is for 135 degrees angle.

So, find area of sector with radius 24 inches. And the find area of arc with r=14 inches.

Then subtract the area of sector with 14 inches  from area of sector with radius as 24 inches.

So, area of sector with r=24 in =\frac{135}{360} *\pi  *24^{2}

Simplify it,

                                                  =216\pi

Now, let's find area of sector with radius 14 inches

Area of sector with r=14 in = \frac{135}{360} *\pi  *14^{2}

Simplify it

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So, area swept by the blade = 216\pi -73.5\pi

Simplify it and use pi as 3.14.....

Area of swept =678.584 - 230.907

                               =447.6769

Round to nearest whole number

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3 0
3 years ago
Peter leaves Mitchell's house traveling 30 mph. Mitchell leaves 15 min later, trying to catch up to peter, going 40 mph. if they
UkoKoshka [18]

Answer:

  45 minutes

Step-by-step explanation:

At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...

  t = d/s

  t = (7.5 mi)/(10 mi/h) = 0.75 h

to catch Peter.

Mitchell will catch Peter in 45 minutes.

__

<em>Alternate Solution</em>

Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:

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_____

You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.

4 0
3 years ago
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Answer:

4.41/ 3 = 1.47 each

Step-by-step explanation:

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