All categories

3 years ago

Find the next three terms of each sequence. 2, -3, -8, -13

Mathematics

2 answers:

GuDViN [60]3 years ago

7 0

Answer:

-18, -23, -28

Step-by-step explanation:

It looks like it is going down by -5

AleksandrR [38]3 years ago

7 0

-18, -23, -28. Just subtract by 5 every time

You might be interested in

Simplify : <br>a) a(2a+b) +a(2a-b )<br> (explain step by step )

Korolek [52]

Answer:

Step-by-step explanation:

Expand then collect the like terms

4 0

4 years ago

Read 2 more answers

I solved some of it but now I don't know if you continue it correctly ... To be performed: (lesson: Raducali of order "n")

nikitadnepr [17]

Answer:

-9

Step-by-step explanation:

$( \sqrt[4]{7} + 2)( \sqrt[4]{7} - 2)( \sqrt{7} + 4) \\ = ( { \sqrt[4]{7} }^{2} - {{2} }^{2} )( \sqrt{7} + 4) [because (a+b)(a-b) = a² - b²]\\ = ( \sqrt{7} - 4)( \sqrt{7} + 4) \\ = { \sqrt{7} }^{2} - {4}^{2}[because (a+b)(a-b) = a² - b²] \\ = 7 - 16 \\ = - 9$

5 0

3 years ago

Read 2 more answers

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are

tankabanditka [31]

The coordinates of point B' are (-3, 6).

<h2>Given that</h2>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

<h3>We have to determine</h3>

What are the coordinates of B' after the translation?

<h3>According to the question</h3>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.

After the given transformation the coordinates of point B' would be:

$\rm B(0, \ 5) = B (0-3, \ 5+1) = B(-3, \ 6)$

Therefore, the coordinates of point B' are (-3, 6).

To know more about Transformation click the link given below.

brainly.com/question/26297555

6 0

3 years ago

Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio

Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

8 0

3 years ago

Which is the approximate solution for the system of equations x+5y=10 and 3x+y=1?

Nina [5.8K]

<h3>Answer: The approximate solution is (-0.36, 2.08).</h3>

Step-by-step explanation:

Given system of equations :

x+5y=10 and 3x+y=1.

Let us solve the system of equation by substitution.

Solving second equation 3x+y=1 for y first.

3x+y=1.

Subtracting 3x from both sides, we get

3x-3x+y=1-3x

y = 1-3x.

Substituting y=1-3x in first equation x+5y=10, we get

x+ 5(1-3x) = 10.

x + 5 -15x =10

-14x +5 = 10.

Subtracting 5 from both sides, we get

-14x +5-5 = 10-5

-14x =5

Dividing by -14 on both sides, we get

-14x/-14=5/-14

x= -0.36.

Plugging x=-0.36 in second equation y=1-3x, we get

y = 1-3(-0.36) = 1+1.08 = 2.08.

<h3>Therefore, approximate solution is (-0.36, 2.08).</h3>

3 0

3 years ago

Read 2 more answers