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Vaselesa [24]
3 years ago
15

PLEASE help (desperate) :(

Mathematics
1 answer:
mars1129 [50]3 years ago
6 0

Answer:

4= \sqrt{16} \\1.5   = \sqrt{2.25}\\8 = 6^{2} /9*2\\1 = \frac{12 - 2}{6 + 4}\\5 = \sqrt{16 + 9} \\9 = 63/3^{2} +|2|

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Akimi4 [234]

The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:

The population P(t) of a culture of bacteria is given by P(t) = –1710t^2+ 92,000t + 10,000, where t is the time in hours since the culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.

Answer:

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Step-by-step explanation:

Equation of population P(t) = –1710t^2+ 92,000t + 10,000

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dP/dt = -2(1710)t + 92000

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Find the critical value by equating dP/dt = 0

-3420t + 92000 = 0

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t = 92000/3420 = 26.90

Check if it really have max value through 2nd derivative

d(dP)/dt^2 = -3420

2nd derivative is negative, hence it has maximum value

So, the time when it is maximum is 26.9 or 27 hours

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Answer:

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