Answer:
my best guess even though no answers i would say bout 12
Step-by-step explanation:
An = a1 + (n-1)*d
n = term to find = 30
a1 = first term = 20
d = common difference = 2
a30 = 20 + (30 - 1) * 2
a30 = 20 + 29 * 2
a30 = 20 + 58
a30 = 78
sn = (n (a1 + a30)) / 2
s30 = (30(20 + 78) / 2
s30 = (30(98) / 2
s30 = 2940/2
s30 = 1470 <===
Answer:
60
Step-by-step explanation:
The least common multiple of 2, 3, 4, 5, and 6 is 3×4×5 = 60.
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2, 3, 5 are primes, there will be at least one factor of each of those in number you're looking for.
4 = 2², so there must be 2 factors of 2 in the number you're looking for.
6 = 2×3, so is already covered by the factors we have listed so far.
LCM = 2²×3×5 = 60
The least number divisible by numbers 2 through 6 is 60.