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lidiya [134]
3 years ago
14

Hi there ummm let me cut to the chase...

Mathematics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

p original investment

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If 5.COS A + 12 sin A=13. prove that tan A= 12÷5<br>​
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Answer:

Ha ha ha ha ha

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So tell me what you want, what you really, really want

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So tell me what you want, what you really, really want

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I wanna really, really, really wanna zigazig ah

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I'll tell you what I want, what I really, really want

So tell me what you want, what you really, really want

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I won't be hasty, I'll give you a try

If you really bug me then I'll say goodbye

Yo I'll tell you what I want, what I really, really want

So tell me what you want, what you really, really want

I wanna, (ha) I wanna, (ha) I wanna, (ha) I wanna, (ha)

I wanna really, really, really wanna zigazig ah

If you wanna be my lover, you gotta get with my friends

(Gotta get with my friends)

Make it last forever, friendship never ends

If you wanna be my lover, you have got to give

(You've got to give)

Taking is too easy, but that's the way it is

So, here's a story from A to Z

You wanna get with me, you gotta listen carefully

We got Em in the place who likes it in your face

You got G like MC who likes it on a

Easy V doesn't come for free, she's a real lady

And as for me, ha you'll see

Slam your body down and wind it all around

Slam your body down and wind it all around

If you wanna be my lover, you gotta get with my friends

(Gotta get with my friends)

Make it last forever, friendship never ends

If you wanna be my lover, you have got to give

(You've got to give)

Taking is too easy, but that's the way it is

If you wanna be my lover

You gotta, you gotta, you gotta, you gotta, you gotta

Slam, slam, slam, slam (make it last forever)

Slam your body down and wind it all around

Slam your body down and wind it all around

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Slam your body down and wind it all around

Slam your body down and zigazig ah

If you wanna be my lover

Step-by-step explanation:

4 0
3 years ago
Evaluate x<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%5Csqrt%7B%28x%5E3%2B9%29%7D" id="TexFormula1" title="x^{2} \sqrt{(x^3
forsale [732]

It sounds like you're talking about an integral, namely

\displaystyle\int x^2\sqrt{x^3+9}\,\mathrm dx

Substitute <em>u</em> = <em>x</em> ³ + 9, so that d<em>u</em> = 3<em>x</em> ² d<em>x</em>. Then

\displaystyle\int x^2\sqrt{x^3+9}\,\mathrm dx=\frac13\int\sqrt{u}\,\mathrm du=\frac13\times\frac23u^{\frac32}+C=\boxed{\frac29(x^3+9)^{\frac32}+C}

7 0
3 years ago
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