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Travka [436]
2 years ago
8

Does the graph represents a function

Mathematics
2 answers:
Aleksandr-060686 [28]2 years ago
5 0

In this situation, we would use something called the vertical line test. In other words, if we can draw a vertical line that passes more than one point on the graph, then the relation is not a function.

If we use the vertical line test in this situation, it is not possible to draw a vertical line that passes through more than one point. Therefore, this does represent a function.

ohaa [14]2 years ago
4 0
You could use a simple pencil test to figure it out.
Place a pencil vertically on the paper, and move it left to right or vise-versa 
When moving it make sure the pencil doesn't hit two points at once if it does it is not a function, but this is not the case

This is a function
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Bingel [31]

These are three equations and three answers.


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Explanation:


Equation A: 20 - 4x = 12 - x + 8 - 3x

The objective is clearing the unknown, which is to isolate it in one side of the equation.

These are the steps and properties that you need to use:


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20 - 4x  = 20 - 4x


2. Use addition property of equality (add 4x on each side).

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Equation B: 5x + 4x - 3  =  24 + 8x (note that I placed the equal sign as it was missing)


1.  Combine like terms on each side:

9x - 3 = 24 + 8x


2. Subtraction property and addition propertiy of equality (subtract 8x and add + 3 on both sides)

x = 27 ↔ solution (neither contradiction nor identity)


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Equation C: 5x + 6 = 2x + 6 + 3x - 15 (note that I placed the equal signs as it was missing)


1. Comitne like terms on the right side:

5x + 6 = 5x - 9


2. Subtraction property of equality (subtract 5x from each side)


6 = - 9 ↔ contradiction


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For your information, when the variable (x) dissapears and fhe final equality is always true (for example 0 = 0, or 20 = 20), the equation is an identity.

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I hope this helps you




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