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NikAS [45]
3 years ago
9

Find the volume of the object.

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

896 inch^3

STAY SAFE, GOD BLESS YOU :)

Step-by-step explanation:

V = l x w x h

= 19 x 2 x 7

= 266 inch^3

= 6 x 15 x 7

= 630 inch^3

Add them both

= 630 + 266

= 896 inch^3

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The altitude of a triangle forms a perpendicular line.<br><br> False<br><br> True
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3 years ago
In the figure below, ⎯⎯⎯⎯⎯⎯⎯⎯,⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯, and ⎯⎯⎯⎯⎯⎯⎯⎯⎯ are medians of △. If KC = 108 and OC = 2n+10, then n=
Nimfa-mama [501]

The question was incomplete. Below you will find the missing content.

In the figure below, BL, AM, and CK are medians of △ABC. If KC = 108 and OC = 2n + 10, then n=

The picture is attached below.

The value of n is 31.

The median is the line connecting the vertex and its midpoint on the opposite side of the triangle.

The intersection of all 3 medians of the triangle is called the centroid.

As we know centroid divides the median in the ratio of 2:1.

In the given picture,

Medians of triangle △ABC are AM, BL, and CK.

So the centroid of the triangle is O.

Given that KC= 108

As the centroid O divides the line KC in 2:1.

Let OC=2x

KO= X

As KC= KO+OC

⇒ 108= x+2x

⇒ 3x=108

⇒ x=108/3

⇒ x=36

Then OC= 2x= 2*36= 72

As given in the question OC= 2n+10

putting the value of OC in above equation

⇒ 72= 2n+10

⇒ 2n= 72-10

⇒ 2n=62

⇒ n=62/2

⇒n=31

Therefore the value of n is 31.

Learn more about the median of the triangle

here: brainly.com/question/2264495

#SPJ10

5 0
2 years ago
How many times larger is 5 × 106 than 5 × 102?<br><br>PLEASE HELP !
Ray Of Light [21]

Divide the largest one by the smallest one : for example, the number 4 is 42=2× larger than the number 2.

Indeed, If you multiply 2 by 42 you'll get 4.

Of course, if a number is n× larger than another, then this other is n× smaller than the first one.

It will of course work with floating point : 0.6×10.6≈0.6×1.6667=1 so 1 is ~1.6667 times larger than 0.6 while 0.6 is ~1.6667 smaller than 1.

plz mark me as the Brainleist plz

5 0
3 years ago
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