3 years ago

PLEASE HELP PLEASE AS FAST AS POSSIBLE PLEASE HELP PLEASE

1 answer:

Pie3 years ago

7 0

The answer is C) $1104.49

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8_murik_8 [283]

Circumference=2pir
r=5
pi=3
circumference=(2)(3)(5)
circumfernce=6(5)
circufmerence=30

answer is 30cm

5 0

3 years ago

GrogVix [38]

Answer:

Wheres the function, what do u mean by captionless image

3 0

3 years ago

sleet_krkn [62]

The answer is 0 because it cancels itself out

3 0

3 years ago

GrogVix [38]

Male 0.271 0.198
Female 0.229 0.302

I think that's right because that's what my quiz said

7 0

3 years ago

MAXImum [283]

We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as x gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if a = 1 and b = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

3 0

2 years ago