Answer:
The function touches the damping factor
at x=
and x=
The x-intercept of f(x) is
at x=
Step-by-step explanation:
Given function is f(x)=
and damping factor as y=
and y=
To find when function touches the damping factor:
For f(x)= and y=
Equating the both the equation,
x=
For f(x)= and y=
Equating the both the equation,
x=
Therefore, The function touches the damping factor x= and x=
To find x-intercept of f(x):
For x-intercept, y=0
f(x)=
y=
Hence, is always greater than zero.
Therefore,
x=
Thus,
The x-intercept of f(x) is at x=
Answer:
i think its D.
A reflection, a rotation, and a translation will prove that shape 2 is congruent to shape 1.
Step-by-step explanation:
You can do substitution 2x-2=x^2 -x -6; isolate all terms on one side 0= x^2 -x-2x -6+2; combine like terms x^2 -3x -4=0; factor the quadratic (x-4)(x+1)=0; each term is zero x-4=0 so x=4 and x+1=0 so x=-1. Now, y=2•4-2=6 and y=2•(-1) -2= -4 ; solutions for the system are ( 4,6) and ( -1, -4)
Answer:
=2x2y−4x
Step-by-step explanation:
Answer:
C is the answer
Step-by-step explanation:
The domain can't be minus. That's the only stipulation. It can be equal to 0 or anything larger than 0. It just can't go into the minus numbers.
0≤x<infinity.
C
