What shows the rational expression written using the least common denominator?

Mathematics

1 answer:

worty [1.4K]2 years ago

4 0

Answer:

Step-by-step explanation:

LCM of 4x² and x² is 4x²

(x+1)/4x² + (x+1)/x2

[(x+1) + 4(x+1)]/4x²

(x+1)/4x² + 4(x+1)/4x²

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How to solve a system of equations using elimination?

Nastasia [14]

If you have a problem like:
4x+2y=20
2x+2y=16
You would subtract
4x-2y=20
-2x+2y=16
You would get the new problum
2x=4
You now want to divide the 2 on both sides to solve for x
x=2

Now that you've solved for X you want to solve for y. So use substitution to solve for y. You would want to substatute the x for the 2 in either of the problums. I'll use the first one.
4(2)+2y=20

You first want to multiply te 4(2) you would get a new problum.
8+2y=20

Now you want to subtract the 8 on both sides.
2y=12

The last step to solve for y is to divide the 2 on both sides.
Y=6

So your answers would be
x=2
y=6

5 0

2 years ago

Karen gave an equal amount of m and m's to herself and four friends. Each person receives m and m's equivalent to the largest on

Mariana [72]

Answer:

Karen had 45 m and m's candy.

Step-by-step explanation:

Let the number of m and m's candy be 'x'.

Now given:

Karen gave an equal amount of m and m's to herself and four friends.

So we can say that;

Number of people m and m's candy distributed equally = 5

Also Given:

Each person receives m and m's equivalent to the largest one digit number.

Now we know that;

Largest one digit number is 9.

So we can say that;

Each person receives m and m's = 9

We need to find number of m and m's Karen have.

Solution:

So we can say that;

Total number of m and m's Karen have is equal to Number of people m and m's candy distributed equally multiplied by number of m and m's can each person receives.

framing in equation form we get;

Total number of m and m's Karen had = $9\times5 = 45$