Question

1. 2x – 3y = -62. 8x + 4y= -56​

Answer 1

Step-by-step explanation:

2x - 3y= - 6........(1)

8x + 4y = - 56......(2) multiply equation (1) all through by 4

8x - 12y = - 24.....(3)

Subtract eq (3) from (3)

8x + 4y - (8x - 12y) = - 56 - (-24)

8x + 4y - 8x + 12y = - 32

8x cancels out

4y + 12y = - 32

16y = - 32

y =-2

Substitute y = - 2 in eq (1)

2x - 3(-2) = - 6

2X +6 = - 6

2x =-6-6

2x = - 12

x =-6

Therefore, x= - 6, y= - 2.

Answer 2

Step-by-step explanation:

[tex]let \\ 2x - 3y = - 6 \: \: \: \: \: eq.1\\ 8x + 4y = - 56 \: \: \: \: \: eq.2 \\ now \: \\ eq.1 \times 4 - eq.2 \\ the \: we \: get \\ - 16y = 32 \\ y = - \frac{16}{8} =-2 \\ and \: \\ x = -6