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2 years ago

How many milliliters are there in 4.5 liters?

Mathematics

1 answer:

Neko [114]2 years ago

7 0

There are 4500 milliliters in 4.5 liters

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Match the sequences with the type of sequence (arithmetic or geometric).

Anni [7]

9, 4, -1, -7
Arithmetic because it has a common difference of 5.

4, 10, 16, 22
Arithmetic because it has a common difference of 6.

2, -6, 18, -54
Geometric because it has a common ratio of -3.

4, 4, 4, 4
Both because it has a common difference of 0 and a common ratio of 1.

Hope this helps :)

3 0

3 years ago

Solve the proportional<br> equation below:<br> x/4 = x-6/3

aleksandrvk [35]

<h2><u>PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>

Apply the means-extremes property of proportions: this allows you to cross multiply:

$\boxed{\mathsf{\dfrac{x}{4} = \dfrac{x - 6}{3}}}$

$\mathsf{\dfrac{x}{4} \searrow \dfrac{x - 6}{3}}$ ‏‏‎ ‏‏‎‎ $\mathsf{\dfrac{x}{4} \nearrow \dfrac{x-6}{3}}$ ‏‏‎‎

$\boxed{\mathsf{3x = 4(x - 6)}}$

Apply the distributive property:

$\mathsf{3x = 4(x-6)}$

$\mathsf{3x = 4(x) - 4(6)}$

$\mathsf{3x = 4x - 24}$

Add 24 to both sides:

$\mathsf{3x + 24 = 4x - 24 + 24}$

$\mathsf{3x + 24 = 4x}$

Substract 3x to both sides

$\mathsf{3x - 3x + 24 = 4x - 3x}$

$\mathsf{24 = 4x - 3x}$

$\large{\boxed{\mathsf{24 = x}}}$

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<h3><u>Answer</u>. The value of x = 24.</h3>

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8 0

2 years ago

Find the missing side (X) round to the nearest hundredth

nata0808 [166]

Answer:

$\displaystyle 18,28 ≈ x$

Step-by-step explanation:

$\displaystyle \frac{x}{11} = csc\:37 \hookrightarrow 11csc\:37 = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x$

$\displaystyle \frac{11}{x} = sin\:37 \hookrightarrow xsin\:37 = 11 \hookrightarrow \frac{11}{sin\:37} = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x$

Information on trigonometric ratios

$\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ$