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S_A_V [24]
2 years ago
14

Write an expression for 213 increased by d.

Mathematics
1 answer:
Tcecarenko [31]2 years ago
6 0

Write an expression for 213 increased by d: 213+d=x

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A cylinder is placed within a cube. The diameter of the cylinder is equal to the length of each side of the cube. What is the vo
pochemuha

The volume of a shape is the amount of space in it.

<em>The volume outside the cylinder, but inside the cube is 214.6 cubic inches</em>

The given parameter is:

l = 10 ---- length of the cube

So, the volume of the cube is:

V_1 = l^3

V_1 = 10^3

V_1 = 1000

The volume of the cylinder is:

V_2 = \pi r^2h

The diameter (d) of the cylinder equals the length of the cube.

This means that:

d = l

d = 10

Divide by 2 to calculate the radius of the cylinder

r = \frac{10}{2}

r = 5

Also, the height of the cube is::

h =l

h =10

So, we have:

V_2 = \pi r^2h

V_2 = \pi \times 5^2 \times 10

V_2 = \pi \times 25 \times 10

V_2 = \pi \times 250

V_2 = 785.4

So, the volume (V) outside the cylinder is:

V = V_1 - V_2

V = 1000 - 785.4

V = 214.6

Hence, the volume outside the cylinder is 214.6 cubic inches

Read more about volumes at:

brainly.com/question/15861918

5 0
2 years ago
Describe a method you can use to find the area of the following shape. Provide specific details in your answer, including coordi
insens350 [35]
The area of figure ABCDEF can be computed as the sum of the areas of trapezoid ACDF and triangle ABC, less the area of trangle DEF.
  trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
  triangle ABC area = (1/2)(AC)(2) = 8
  triangle DEF area = (1/2)(DF)(2) = 5

Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42

The actual area of ABCDEF is 42 square units.

7 0
2 years ago
Will mark brainliest
VMariaS [17]

Answer:

Interquartile range => 7

Third quartile => 22

Range => 13

First quartile => 15

Step-by-step explanation:

Order your data set, from the least amount to the highest amount:

$12, $14, $15, $15, $15, $15, $16, $22, $24, $25

Interquartile range (IQR) = third quartile (Q3) - first quartile (Q1)

Q1 = the middle value of the lower part of the data set, from the median to your left.

Q3 = the middle value of the upper part of the data set, from the median to your right.

The median lies between the 5th and 6th value that is enclosed in the parenthesis below:

$12, $14, ($15), $15, $15,[Median], $15, $16, ($22), $24, $25

The median divides the data set into upper and lower part.

Median = \frac{15 + 15}{2} = 15

First quartile: Q1 = $15

Third quartile: Q3 = $22

IQR = $22 - $15 = $7

Range = highest amount - least amount = 25 - 12 = $13

3 0
3 years ago
Determine the slope between the points (5, -5) and (-1, 7)
meriva

Answer:

slope = 3

Step-by-step explanation:

5 - x1 -5 - y1

-1- x2 7 - y2

m= y2 - y1 / x2 - x1

m= 7 - (-5) / -1 -(-5)

m= 12 / 4

m= 3

4 0
2 years ago
Read 2 more answers
A sample of 92 observations is taken from a process (an infinite population). the sampling distribution of x̄ is approximately n
Sindrei [870]
It is normal based on the Central Limit Theorem. According to the theorem, an appropriately big sample (infinite) size from a population with a limited level of variance, the average of all samples from the same populace will be roughly equivalent to the mean of the population.
6 0
3 years ago
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