Solve for the valuable. 7x - 3 = -9

Mathematics

2 answers:

Alexxandr [17]2 years ago

8 0

I think it’s -6/7 the 6 at the top and 7 at the bottom hope it helps

mylen [45]2 years ago

3 0

Answer:

x = -6/7

Step-by-step explanation:

7x - 3 = -9

+3 +3

7x = -6

x = -6/7

If this answer is correct, please make me Brainliest!

You might be interested in

2(x + 7) + 3x = 12<br> What is the first step in solving this equation for x?

yawa3891 [41]

First step is expand by using distributive property
<span>2(x + 7) + 3x = 12

step 1:
2x + 14 + 3x = 12</span>

7 0

2 years ago

Read 2 more answers

Consider a game in which a participant pays $2 to roll a die. The participant receives $3 if they roll a 1 (i.E. They go up by a

Sauron [17]

Answer:

The expected monetary value of a single roll is $1.17.

Step-by-step explanation:

The sample space of rolling a die is:

S = {1, 2, 3, 4, 5 and 6}

The probability of rolling any of the six numbers is same, i.e.

P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = $\frac{1}{6}$

The expected pay for rolling the numbers are as follows:

E (X = 1) = $3

E (X = 2) = $0

E (X = 3) = $0

E (X = 4) = $0

E (X = 5) = $0

E (X = 6) = $4

The expected value of an experiment is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected monetary value of a single roll as follows:

$E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17$