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Stella [2.4K]
3 years ago
7

Write 72,300,000 in scientific notation

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0

72.3x10^{6}
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Mr. Perez ordered 12 new jerseys for the middle school baseball team . Each jersey costs the same amount. He paid \$|O for shipp
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each jersey was 15 dollars.

Step-by-step explanation:

190-10= 180

180/12= 15

hope this helps!!

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Is my answer correct? If its not, would you mine telling me what is correct?
Luden [163]

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Sorry but you have the y and x mixed up

Step-by-step explanation:

You have them mixed up

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there is a 750 ml bottle of concentrate orange squash it is enough to make fifteen 250 ml glasses of diluted orange drink how mu
Anarel [89]
15 \times 250 \ ml=3750 \ ml
Fifteen 250 ml glasses contain 3750 ml of the drink, and 750 ml of orange squash.
3750 \ ml - 750 \ ml=3000 \ ml
There are 3000 ml of water in 3750 ml of the drink.

3000 ml of water - 3750 ml of the drink
x l of water - 10 l of the drink

\frac{3000 \ ml}{3750 \ ml}=\frac{x \ l}{10 \ l} \\
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8 litres of water are needed to make 10 litres of this drink.
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3 years ago
In the figure, AB ║ CD and m∠3 = 120°.
zlopas [31]

Yes, 60° is right.

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4 years ago
Jaclyn plays singles for the varsity tennis team where she won the sudden death tie breaker point with a cross-court passing sho
podryga [215]

Answer:

Incomplete question

Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.

a. Determine the pre-collision momentum of the ball.

b. Determine the post-collision momentum of the ball.

c. Determine the momentum change of the ball.

Answer:

A. 1.5353kgm/s

B. 1.6963kgm/s

C. 0.161kgm/s

Step-by-step explanation:

A. The pre-collision momentum of the ball = mass of ball × velocity of ball

Mass of ball = 57.5g = 0.0575kg

Velocity of ball = 26.7m/s

Pre-collision momentum of ball = 0.0575×26.7

= 1.5353kgm/s

B. Post collision momentum of the ball = mass of ball × velocity of ball after impact

Velocity of ball after impact = 29.5m/s

Post collision momentum of ball after impact = 0.0575×29.5

= 1.6963kgm/s

C. Momentum change of ball = momentum after impact - momentum before imlact

= 1.6963kgm/s - 1.5353kgm/s

= 0.161kgm/s

7 0
3 years ago
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