Answer:
The value of the expression at x=5 is 10
Step-by-step explanation:
The given expression is 
Let us simplify this expression.
Distribute -2 over the parentheses, we get

Now, substitute x = 5, we get

On simplifying, we get

The value of the expression at x=5 is 10
Answer:
9:6 27:18 and 81: 54
Step-by-step explanation:
Answer:
its alot to explain but i will try to make it as simple as possible
Step-by-step explanation:
your first goal is to make each problem into the form ax^2+bx+c=0
number 1, 2, 7 and 8 is already done for you
now all you have to do is plug in each number in the standard form into the quadtratic formula.
basically at this point you can just use your calculator to do the rest of the work. dont forget parentheses so it doesnt get confused...
or you can perform the algebraic work.. its all just a matter of plugging in the right numbers into the quadratic formula...
cant really do the work for you since im on my phone. but yeah all you need to do step one is transform each problem into ax^2+bx+c=0 form
then step 2, plug in each number in to the quadtratic formula. from there calculate using basic algebraic rules
The complete question is
"What is the value of this expression when c= -4 and d= 10?
1/4 (c^3+d²)
A.2
B.9
C.21
D.41"
The value of this expression when c = -4 and d = 10 will be option B 9.
<h3>What is a simplification of an expression?</h3>
Usually, simplification involves proceeding with the pending operations in the expression.
Simplification usually involves making the expression simple and easy to use later.
The given expression is

Hence, the value of this expression when c = -4 and d = 10 will be option B 9.
Learn more about an expression here:
brainly.com/question/1249625
#SPJ1
Answer:
The ordinate of B exceeds the ordinate of A by 7
Step-by-step explanation:
Let
A(x1,y1),B(x2,y2)
where
x1 is the abscissa of A
x2 is the abscissa of B
y1 is the ordinate of A
y2 is the ordinate of B
we know that


so
-----> equation A
----> equation B
substitute equation B in equation A
therefore
The ordinate of B exceeds the ordinate of A by 7