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malfutka [58]
3 years ago
10

(10.02)

Mathematics
1 answer:
ollegr [7]3 years ago
6 0
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

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Answer:

= (∛(100x))/5

Step-by-step explanation:

Given the expression; ∛(4x/5)

To simplify this we need to make denominator a perfect cube.

So multiply and divide 25 inside the cube root, so that the denominator will become a perfect cube of 5.

∛(4x/5) = ∛((4x/5)×(25/25))

            = ∛(100x/125)

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Andreyy89

Carl and Rose' balconies make up the base of an isosceles triangle.

Their distances from the flagpole is the same.

From the question, we understand that:

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k+7=34
Subtract k from both sides.
k=27
5 0
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yKpoI14uk [10]

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