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4 years ago

10

(10.02)

1 answer:

ollegr [7]4 years ago

6 0

<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

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Given the function how do I solve

BARSIC [14]

Answer: (a) -7 (b) $\bold{\dfrac{4}{25}}$ (c) $\bold{-\dfrac{5}{2}}$ (d) 4

Step-by-step explanation:

A) f(x) = 2x - 3 when x is between -5 and -2 (including -5 and -2)

B) f(x) = x² when x is between -2 and 2 (including 2)

C) $f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}$ when x is between 2 and 5 (including 5)

a) Equation A includes x = -2

f(x) = 2x - 3

f(-2) = 2(-2) - 3

= -4 - 3

= -7

b) Equation B includes x = $-\dfrac{2}{5}$

f(x) = x²

$f\bigg(-\dfrac{2}{5}\bigg) = \bigg(-\dfrac{2}{5}\bigg)^2$

$=\dfrac{4}{25}$

c) Equation C includes x = 4

$f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}$

$f(4)=-\dfrac{3}{2}(4)+\dfrac{7}{2}$

$=-\dfrac{12}{2}+\dfrac{7}{2}$

$=-\dfrac{5}{2}$

d) Try each equation to see if x falls within the values given.

A) f(x) = 2x - 3

-2.5 = 2x - 3

0.5 = 2x

0.25 = x NOT VALID since x should be between -5 and -2

B) f(x) = x²

-2.5 = x²

$\sqrt{-2.5}=x$ NOT VALID since x cannot be an imaginary number

C) $f(x)=-\dfrac{3}{2}x+\dfrac{7}{2}$

$-\dfrac{5}{2}=-\dfrac{3}{2}x+\dfrac{7}{2}$

$-\dfrac{12}{2}=-\dfrac{3}{2}x$

$-\dfrac{12}{2}\bigg(\dfrac{2}{3}\bigg)=x$

$4 = x$ VALID since x is between 2 and 5

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UkoKoshka [18]

Answer:

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Step-by-step explanation:

you would do 3.14 times the radius times the formula and you would get you answer you radius is half of the formula

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