Answer:
15.74% of women are between 65.5 inches and 68.5 inches.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What percentage of women are between 65.5 inches and 68.5 inches?
This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.
X = 68.5



has a pvalue of 0.9987
X = 65.5



has a pvalue of 0.8413
So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.
Answer:
0.6042 or 29/48
Step-by-step explanation:
-5/16 = -0.3125
7/24 = 0.2917
0.2917 - -0.3125 = 0.6042
0.6042 ≅ 29/48
Answer:
2+2=4
Step-by-step explanation:
My day is good thx
Answer:
5 & 8
Step-by-step explanation:
x-y = 3 -> x = 3+y
x+y = 13 = 3+y+y -> 3+2*y = 13
2*y = 10 -> y = 5
-> x = 3+y = 8