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3 years ago

9

What is 26 divided by 988

1 answer:

olga2289 [7]3 years ago

5 0

Its an absurd decimal, which I'm pretty sure you don't want but will give to you anyway. Its roughly 0.02631578947...

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Which of the following best describes the slope of the line below? -5 O A. Undefined O B. Zero O c. Positive OD. Negative

lana66690 [7]

negative is the answer

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3 years ago

HELPPPP ILL MARK YOU BRAINLIST SHOW WORK SHOW WORK

Vitek1552 [10]

You multiply the binomial by the whole trinomial.

So 5x^2 (5x^3 - 6x^2 - 5) and then -2x (5x^3 - 6x^2 - 5)

then solve so it is:
25x^5 - 30x^4 - 25x^2 - 10x^4 + 12x^3 + 10x.

Then you simplify to:
25x^5 - 40x^4 + 12x^3 - 25x^2 + 10x

Your Welcome

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3 years ago

Which statements are correct about quadrilaterals?

Serjik [45]

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3 years ago

Solve and check the following linear equation. 8x-(6x-7)=21

uranmaximum [27]

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Your friend Alex was solving the equation 2x^2+3x=20 and the work below. Tragically, she made an error in her work. First, expla

earnstyle [38]

Answer:

Her error is that For solving by Completing the square method.

She has not made the Coefficient of x² as 1.

Therefore,

$x=\dfrac{-3+13}{4}=\dfrac{10}{4}=2.5\ OR\ x=\dfrac{-3-13}{4}=\dfrac{-16}{4}=-4$

Step-by-step explanation:

Alex was solving the equation

$2x^{2}+3x=20$

She is solving for x by Completing the square method

Her error is that For solving by Completing the square method

First step is to make Coefficient of x² as 1 ( one )

She has not made the Coefficient of x² as 1

The Require steps for the equation by Completing the square method are

Step 1 : Given

$2x^{2}+3x-20=0$

Step 2: Divide the whole by 2 we get

$x^{2}+\dfrac{3}{2}x-10=0$

Step 3 : Add 10 to both side

$x^{2}+\dfrac{3}{2}x-10+10=0+10\\\\x^{2}+\dfrac{3}{2}x=10$

Step 4 : Add $(\dfrac{1}{2}coefficient\ of\ x)^{2}=\dfrac{9}{16}$ to both the side.

$x^{2}+\dfrac{3}{2}x+\dfrac{9}{16}=10+\dfrac{9}{16}\\\\x^{2}+2\times \dfrac{3}{4}x+(\dfrac{3}{4})^{2}=\dfrac{169}{16}$

Step 5 : We have A² + 2AB + B² = (A+B)²

$(x+\dfrac{3}{4})^{2}=\dfrac{169}{16}$

Step 6 : Taking Square root

$(x+\dfrac{3}{4})=\pm \sqrt{\dfrac{169}{16}}=\pm \dfrac{13}{4}$

Step 7 : Subtract $\dfrac{3}{4}$ both side

$x+\dfrac{3}{4}-\dfrac{3}{4}=-\dfrac{3}{4}\pm \sqrt{\dfrac{169}{16}}=\pm \dfrac{13}{4}\\\\x=-\dfrac{3}{4} \pm \dfrac{13}{4}$

Step 8 : Finally we get

$x=\dfrac{-3+13}{4}=\dfrac{10}{4}=2.5\ OR\ x=\dfrac{-3-13}{4}=\dfrac{-16}{4}=-4$

Therefore,

$x=\dfrac{-3+13}{4}=\dfrac{10}{4}=2.5\ OR\ x=\dfrac{-3-13}{4}=\dfrac{-16}{4}=-4$

5 0

3 years ago