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crimeas [40]
3 years ago
5

Hosting a breakfast brunch for 25 people, you plan to serve scrambled eggs. The grocery store sells eggs in cartons, and each ca

rton can feed 4 people. How many cartons of eggs must you buy to ensure each guest a serving? ​
Mathematics
2 answers:
ratelena [41]3 years ago
3 0
You need 7 cartons, 4•7=28 so you’ll be sure to have enough:)
aleksandrvk [35]3 years ago
3 0

Answer:

Required number of cartons to be ordered = 7

Step-by-step explanation:

Number of peoples for which the breakfast is being hosted = 25

The grocery store sells the eggs in cartons.

Number of people fed using one carton = 4

And, we need to find number of cartons which is to be ordered to ensure each guest receives serving.

4 peoples are served using one carton.

⇒ <u><em>1 people is served by using 1/4 cartons</em></u>

<u><em> 25 people are served using 1/4 x 25 = 6.25 cartons</em></u>

Since, Cartons cannot be ordered in decimals so number of cartons that must be ordered to ensure each guest a serving is 7

Hence, Required number of cartons to be ordered = 7

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The timekeeper for a particular mile race uses a stopwatch to determine the finishing times of the racers. He then calculates th
insens350 [35]

Answer:

300 seconds = 5 minutes

Step-by-step explanation:

At first convert the time in minutes which is

5.75 * 60 = 345 seconds

No as the average is 345 seconds at starts from 45 so we subtract that time from 45 seconds

345-45 = 300 seconds (Mean)

So 300 seconds = 300/60 = 5 minutes

So the Accurate mean is 5 minutes

7 0
3 years ago
Hello please help me quick!
Ronch [10]

Answer:

Answer is A

Step-by-step explanation:

subtract 15 1/4 and 2 2/3

4 0
3 years ago
Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in
Alborosie

Answer:

a) Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

b) z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

p_v =P(Z

c) So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

\hat p=0.46 estimated proportion of American families owning stocks or stock funds

p_o=0.53 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:  

Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z

Part c  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

7 0
3 years ago
Please awnser two more questions after this
xenn [34]

Answer:

J(-9,-5)

K(-9,3)

L(0,-2)

M(0,-5)

6 0
2 years ago
The figure below shows two pair of congruent triangles. ΔDEF ≅ ______. ΔWXY ΔWYX ΔYWX ΔYXW
Alexandra [31]

Answer:

YXW

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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