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Anna11 [10]
3 years ago
7

Help Please!

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

y=3x

Step-by-step explanation:

I took the test

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an airport charges an additional fee for a piece of luggage that weighs more than 50 lbs write an inequality that shows the weig
nekit [7.7K]

Answer:

X ≤ 50

Step-by-step explanation:

Since the additional fee for a piece of luggage is only charged if it weighs more than 50 lbs, than Michael's suitcase weight must be less than, or equal to, 50 lbs.  Using 'X' as the weight of Michael's suitcase in pounds:

X ≤ 50

'X' is less than or equal to 50 lbs

4 0
3 years ago
What are the determinants for solving this linear system?<br> 5x + 3y = 17<br> −8x − 3y = 9
Ksivusya [100]
For this case we have the following system of equations:
 5x + 3y = 17
 -8x - 3y = 9
 We can rewrite the system like:
 Ax = b
 Where,
 A = [5   3; -8   -3]
 b = [17; 9]
 x = [x; y]
 The determinant of matrix A is given by:
 lAl = ((5) * (- 3)) - ((3) * (- 8))
 lAl = (-15) - (-24)
 lAl = -15 + 24
 lAl = 9
 Answer:
 
The determinant for solving this linear system is:
 
lAl = 9
3 0
2 years ago
Read 2 more answers
Solve the equation.<br> 1. -66 = -9n+ 16 + 4<br> n = 4<br> b. n = 10
prisoha [69]

Answer:

b

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Captain Emily has a ship, the H.M.S Crimson Lynx. The ship is five furlongs from the dread pirate Umaima and her merciless band
LenaWriter [7]

Answer:

The probability that the pirate misses the captain's ship but the captain hits = 0.514

Step-by-step explanation:

Let A be the event that the captain hits the pirate ship

The probability of the captain hitting the pirate ship, P(A) = 3/5

Let B be the event that the pirate hits the captain's ship

The probability of the pirate hitting the captain's ship P(B) = 1/7

The probability of the pirate missing the captain's ship, P'(B) = 1 - P(B)

P'(B) = 1 - 1/7 = 6/7

The probability that the pirate misses the captain's ship but the captain hits = P(A) * P(B) = 3/5 * 6/7

= 0.514

5 0
3 years ago
In the diagram m angle ACB = 61<br> Find m angle BCD
Marina86 [1]

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

90-61=61-61+angle(BCD)

angle(BCD)=29................Answer


7 0
3 years ago
Read 2 more answers
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